One mol is 6.02214179×1023 so about 3*10-4 (3 times ten to the minus 4) moles
Yes, 2 times 3 atoms in 2O3 = 6 atoms = 3 times 2 atoms in 3O2
2.01x10^22 atoms x 1 mole/6.02x10^23 atoms = 0.0334 moles
1.20x10^24 atoms x 1 mole/6.02x10^23 atoms = 1.99 moles
In 3 moles of CH4, there are 18.06 x 10^23 times Hydrogen atoms.
2.09*10^22 This is how you figure it out: 3.74g divided by 107.87(the atomic mass of silver). Then you multiply the number you get by 6.022x10^23 (Avogadros number). And that's your answer.
The answer is 0,465 moles.
The number of moles is 0,528.
10.08 moles (there are six carbon atoms per molecule of C6H6, hence, six times the number of moles of carbon can be produced).
avogadro's constant is the number of atoms (or molecules, as in the case of compounds) contained in a mole of a substance. roughly, then, in 4 moles of gold there are 4 x 6.02 x 10 to the 23rd power atoms or two septillion, four hundred eight sextilllion atoms. (2,408,000,000,000,000,000,000,000) see also: http://en.wikipedia.org/wiki/Avogadro_constant
1.51 X 1015 atoms (1 mole/6.022 X 1023) = 2.51 X 10 -9 moles ===============
If the chlorine is in its normal state of diatomic molecules, there are 16.0 moles of chlorine atoms in 8.00 moles of chlorine. The number of atoms is then 16 times Avogadro's number = 9.64 X 1024, to the justified number of significant digits.
Using avagadro's number of 6.022 x 10 to the 23rd atoms/mole. The answer is 1.99 moles of gold