.05 L x 342 (this is the molecular weight of sucrose) x 1.75 = 29.925g
A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
about 1.4*10^25
The lysozyme will break down the peptidoglycan layer of the gram positive bacterium, causing it to lose its structural integrity and burst. The presence of sucrose will create a hypertonic environment, leading to osmotic dehydration of the bacterium due to water moving out of the cell, adding to its demise.
False. A planet with an albedo of 10 percent reflects 10 percent of the sunlight that strikes it and absorbs the other 90 percent.
To make a percent sucrose solution, dissolve a specific weight of sucrose in a specific volume of water. For example, to make a 10% sucrose solution, dissolve 10 grams of sucrose in 90 mL of water. The formula to calculate the amount of sucrose needed is: (percent sucrose/100) x volume of solution = weight of sucrose (in grams).
There are 1.81 x 10^24 sucrose molecules in 3.0 moles of sucrose.
25.263157895 g @ 10 % + 94.736842105 g @ 0.5 % = total 3 g out of 120 g total = 2.5 %
.05 L x 342 (this is the molecular weight of sucrose) x 1.75 = 29.925g
10%
A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
about 1.4*10^25
In 2.00 moles of sucrose, there are approximately 1.21 x 10^24 atoms. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles (2.00). Each mole of sucrose contains 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms.
Molarity=[w/GMW]*[1000/volume(in mL)] 0.5=[w/342]*[1000/100]=17.1g similarly,34.2g sucrose is to dissolved in water and made up to 100mL to make 1molar solution and 171g to make 5molar solution.
10% + 10% = 20%
10 percent is a 10th of something, so 10 percent of $10 is $1.
10 percent percent of 86.50 = 0.0865