.05 L x 342 (this is the molecular weight of sucrose) x 1.75 = 29.925g
To prepare a standard for total soluble sugar, dissolve a known weight of a pure sugar (such as sucrose) in a specific volume of distilled water to create a concentrated solution. For example, dissolve 10 grams of sucrose in 100 milliliters of water to create a 10% (w/v) solution. Mix thoroughly to ensure complete dissolution, and further dilute this solution to desired concentrations for calibration purposes in your analysis. Store the standard solution in a tightly sealed container, protected from light, to maintain its stability.
A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
To find the number of sucrose molecules in 3.0 moles of sucrose, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Multiply the number of moles by Avogadro's number: [ 3.0 , \text{moles} \times 6.022 \times 10^{23} , \text{molecules/mole} \approx 1.81 \times 10^{24} , \text{molecules}. ] Therefore, there are approximately (1.81 \times 10^{24}) molecules of sucrose in 3.0 moles.
about 1.4*10^25
To make a percent sucrose solution, dissolve a specific weight of sucrose in a specific volume of water. For example, to make a 10% sucrose solution, dissolve 10 grams of sucrose in 90 mL of water. The formula to calculate the amount of sucrose needed is: (percent sucrose/100) x volume of solution = weight of sucrose (in grams).
There are 1.81 x 10^24 sucrose molecules in 3.0 moles of sucrose.
25.263157895 g @ 10 % + 94.736842105 g @ 0.5 % = total 3 g out of 120 g total = 2.5 %
.05 L x 342 (this is the molecular weight of sucrose) x 1.75 = 29.925g
10%
To prepare a standard for total soluble sugar, dissolve a known weight of a pure sugar (such as sucrose) in a specific volume of distilled water to create a concentrated solution. For example, dissolve 10 grams of sucrose in 100 milliliters of water to create a 10% (w/v) solution. Mix thoroughly to ensure complete dissolution, and further dilute this solution to desired concentrations for calibration purposes in your analysis. Store the standard solution in a tightly sealed container, protected from light, to maintain its stability.
A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
To find the number of sucrose molecules in 3.0 moles of sucrose, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Multiply the number of moles by Avogadro's number: [ 3.0 , \text{moles} \times 6.022 \times 10^{23} , \text{molecules/mole} \approx 1.81 \times 10^{24} , \text{molecules}. ] Therefore, there are approximately (1.81 \times 10^{24}) molecules of sucrose in 3.0 moles.
about 1.4*10^25
Molarity=[w/GMW]*[1000/volume(in mL)] 0.5=[w/342]*[1000/100]=17.1g similarly,34.2g sucrose is to dissolved in water and made up to 100mL to make 1molar solution and 171g to make 5molar solution.
In 2.00 moles of sucrose, there are approximately 1.21 x 10^24 atoms. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles (2.00). Each mole of sucrose contains 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms.
To prepare a 500g solution that is 10 percent sugar by mass, you need to calculate the mass of sugar required. Since 10% of 500g is 50g, you would weigh out 50g of sugar. Then, you would add enough water to the sugar to reach a total mass of 500g, which means adding 450g of water. Mix the sugar and water thoroughly until the sugar is fully dissolved.