To find the number of sucrose molecules in 3.0 moles of sucrose, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Multiply the number of moles by Avogadro's number:
[ 3.0 , \text{moles} \times 6.022 \times 10^{23} , \text{molecules/mole} \approx 1.81 \times 10^{24} , \text{molecules}. ]
Therefore, there are approximately (1.81 \times 10^{24}) molecules of sucrose in 3.0 moles.
To find the number of molecules in 30 liters of methane (CH₄), we can use the ideal gas law, which states that 1 mole of gas occupies 22.4 liters at standard temperature and pressure. Therefore, 30 liters of methane is approximately 1.34 moles (30 L / 22.4 L/mol). Since one mole contains about (6.022 \times 10^{23}) molecules (Avogadro's number), 1.34 moles of methane contains approximately (8.06 \times 10^{23}) molecules.
Each glucose molecule contains 6 carbon atoms. Thus we need 18 molecules of CO2 to make 3 molecules of glucose.
To prepare a 30% sucrose solution, dissolve 30g of sucrose in enough water to make a total of 100mL solution. Measure out the correct amount of sucrose using a balance, then add water and stir until the sucrose is completely dissolved.
This amount may be different because rust is not a clearly definite compound.
From the balanced equation, we can see that 3 moles of CO2 are formed for every 1 mole of C3H4 that reacts. Therefore, if 10 moles of C3H4 react, 30 moles of CO2 would be formed (10 moles C3H4 x 3 moles CO2/1 mole C3H4).
1 mole equals 6.022 x 10 to the 23 molecules
To find the number of molecules in 30 liters of methane (CH₄), we can use the ideal gas law, which states that 1 mole of gas occupies 22.4 liters at standard temperature and pressure. Therefore, 30 liters of methane is approximately 1.34 moles (30 L / 22.4 L/mol). Since one mole contains about (6.022 \times 10^{23}) molecules (Avogadro's number), 1.34 moles of methane contains approximately (8.06 \times 10^{23}) molecules.
To find the number of molecules in 50.0 g of CH2O, you need to first calculate the number of moles of CH2O using its molar mass (30.03 g/mol). Next, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles into molecules. Therefore, 50.0 g of CH2O contains approximately 1.66 x 10^24 molecules.
If you have 30 molecules of sodium reacting with aluminum chloride (AlCl3), they will produce 10 molecules of aluminum. This is because the balanced equation shows that 3 moles of sodium react with 1 mole of aluminum, producing 1 mole of aluminum.
30 moles
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. So, in 30 liters of methane, there would be 30/22.4 = 1.3393 moles. One mole of methane contains 6.022 x 10^23 molecules, therefore 30 liters of methane at STP would contain 1.3393 * 6.022 x 10^23 = 8.07 x 10^23 molecules.
Each glucose molecule contains 6 carbon atoms. Thus we need 18 molecules of CO2 to make 3 molecules of glucose.
From the balanced equation, 2 moles of A3 react with 3 moles of B2 to produce 6 moles of AB. Therefore, if 10 moles of A3 are reacted, the ratio of moles of AB produced would be (10 moles A3 / 2 moles A3) * 6 moles AB = 30 moles AB.
To determine the number of molecules in 60 g of ethane, you need to first calculate the number of moles of ethane using its molar mass (30 g/mol). Then, you can convert moles to molecules using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
One molecule of sucrose can be broken down into glucose and fructose, both of which can then enter glycolysis to produce ATP. Overall, the breakdown of 1 molecule of sucrose yields about 30-32 ATP.
For every 2 moles of A3, 3 moles of B2 react to form 6 moles of AB. Since we have 10 moles of A3, we need to double the moles of B2 reacting, which would be 15 moles of B2 to fully react with the 10 moles of A3. This would produce 30 moles of AB.
None. There is no hydrogen in sodium