You can plot the "days to orbit sun" vs "average distance" for all known planets on a graph and see the relationship using a trend line. A planet at around 3 AU (450 million km) can then be seen to orbit the sun in around 1850 days or 5 years (assuming its our sun and not another star as the mass size influences the orbit). To get a more mathematical prediction, you could use Keplars laws of planetary motion.
The distance of a planet from the sun affects its orbital period. Generally, the farther a planet is from the sun, the longer its orbital period will be. This relationship is described by Kepler's third law of planetary motion, which states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun.
A planet's orbital period is related to its distance from the Sun by Kepler's third law, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. For an orbital period of 3 million years, the planet would need to be located at a distance of approximately 367 AU from the Sun.
Time2 = Distance3 (if time is in years and distance in AU) 112 = distance3 Distance = 4.946 AU The closet planet with that orbit is Jupiter - it has a year (period) of 11.86 earth years and is 778 million km (5.2 AU) from the sun.
The orbital period of the planet Mercury around the sun is approximately 88 Earth days. Mercury has a relatively short orbital period due to its proximity to the sun, which causes it to move quickly in its orbit.
Yes, spot on, good guess . .
The approximate orbital period of an object at a distance of 65 AU from the sun would be around 177 years. This corresponds to Kepler's third law of planetary motion, which relates the orbital period of a planet to its distance from the sun.
The distance of a planet from the sun affects its orbital period. Generally, the farther a planet is from the sun, the longer its orbital period will be. This relationship is described by Kepler's third law of planetary motion, which states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun.
A planet's orbital period is related to its distance from the Sun by Kepler's third law, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. For an orbital period of 3 million years, the planet would need to be located at a distance of approximately 367 AU from the Sun.
A year (or orbital period) is defined as the period it takes a planet to orbit the Sun.
Mercury is the closest planet to the Sun and has an orbital period of 88 Earth days. (Pluto in contrast has an orbital period of about 248 Earth years.)
Time2 = Distance3 (if time is in years and distance in AU) 112 = distance3 Distance = 4.946 AU The closet planet with that orbit is Jupiter - it has a year (period) of 11.86 earth years and is 778 million km (5.2 AU) from the sun.
Yes, the square of the orbital period of a planet is proportional to the cube of the average distance of the planet from the Sun. This relationship is known as Kepler's Third Law of Planetary Motion. It describes the mathematical relationship between a planet's orbital period and its average distance from the Sun.
To calculate the orbital period of a planet, you can use Kepler's third law of planetary motion. The formula is T2 (42 r3) / (G M), where T is the orbital period, r is the average distance from the planet to the sun, G is the gravitational constant, and M is the mass of the sun. Simply plug in the values for r and M to find the orbital period of the planet.
That is that planet's "year", or its orbital period.
The orbital period of the planet Mercury around the sun is approximately 88 Earth days. Mercury has a relatively short orbital period due to its proximity to the sun, which causes it to move quickly in its orbit.
Yes, spot on, good guess . .
Kepler's third law of planetary motion states that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun. This relationship allows us to predict the orbital period of a planet based on its distance from the sun, and vice versa.