The equation for half-life is ...
AT = A0 2 (-T/H)
... where A0 is the starting activity, AT is the activity at some time T, and H is the half-life in units of T.
There are other versions, but they all work out the same way. Using this version, with 2 as the base instead of e, makes it easier to remember.
After 2 half-lives, you would have 25% of the original amount remaining. Each half-life reduces the amount by half, so after two half-lives, you would have 25% left (50% reduced by half twice).
After 2 half-lives (two half-lives of tritium is 12.32 x 2 = 24.64 years), the initial 10g sample of tritium would have decayed by half to 5g.
6.5 half-lives.
91.16% of the daughter product has formed after 3.5 half lives.
After 2 half-lives, 25% of the original amount of thorium-234 will remain. This is because half of the substance decays in each half-life period.
To calculate the age of a bone using its half-life, you first determine the amount of the radioactive isotope remaining in the bone compared to the original amount. Then, you use the half-life of the isotope to find out how many half-lives have elapsed, which can be calculated using the formula: ( \text{Age} = \text{Half-life} \times n ), where ( n ) is the number of half-lives. By knowing how much of the isotope remains, you can calculate ( n ) using logarithmic functions to solve for the age of the bone.
To calculate the amount of thorium remaining after 2 half-lives, you use the formula: amount = initial amount * (1/2)^n, where n is the number of half-lives. If we assume the initial amount is 1 gram, after 2 half-lives, there would be 0.25 grams of thorium remaining.
Plutonium-239, a common isotope of plutonium, has a half-life of about 24,100 years. To calculate the number of half-lives, divide the total time by the half-life. For example, in 48,200 years, there would be 2 half-lives.
The half-life forms a type of clock used to calculate time passed.
If the half-life of carbon-14 is 5,370 years and 6 half-lives have passed, you can calculate the age of the fossil by multiplying the half-life by the number of half-lives: 5,370 years × 6 = 32,220 years. Therefore, the fossil is approximately 32,220 years old.
1/8 = (1/2)3 which is in the form (1/2)n where n is the number of half lives undergone. Therefore the substance has passed three half lives
How the Other Half Lives was created in 1890.
How the Other Half Lives was created in 1890.
To determine how many half-lives have passed, you would need to divide the total time passed by the half-life of the substance. The result would give you the number of half-lives that have occurred.
After 2 half-lives, you would have 25% of the original amount remaining. Each half-life reduces the amount by half, so after two half-lives, you would have 25% left (50% reduced by half twice).
After 2 half-lives (two half-lives of tritium is 12.32 x 2 = 24.64 years), the initial 10g sample of tritium would have decayed by half to 5g.
3 At the end of the first half life, there will theoretically be 50% remaining. 2 half lives: 25% 3 half lives:12.5 %