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What mass of oxygen in grams is in 147.2 grams of glucose?
To determine the mass of oxygen in 147.2 grams of glucose (C6H12O6), we need to consider the molecular formula of glucose. For each mole of glucose, there are 6 moles of oxygen atoms. The molar mass of glucose is approximately 180.16 g/mol. Thus, the mass of oxygen in 147.2 grams of glucose would be (6/180.16) * 147.2 = approximately 4.88 grams.
If 154 grams of glucose are dissolved to yield one liter of solution what is the molarity of the solution?
Molarity = moles of solute/Liters of solution Find moles glucose, which is molecular formula------C6H12O6 154 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.8548 moles C6H12O6 Molarity = 0.8548 moles C6H12O6/1 Liter = 0.855 M glucose ---------------------------
What is the molarity of an aqueous solution containing 32.8 g of C6H12O6 in 1.0 L of solution?
Find moles of glucose. 32.8 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.18206 moles C6H12O6 Molarity = moles of solute/Liters of solution M = 0.18206 moles C6H12O6/1.0 L = 0.18 M C6H12O6
How many grams of Glucose molecular formula C6O6H12 should you dissolve in 1 liter of water to get 1 molar solution?
To make a 1 molar solution of glucose (C6H12O6) in 1 liter of water, you would need to dissolve 180 grams of glucose. This is because the molar mass of glucose is 180 g/mol, so 1 mole of glucose weighs 180 grams.
How many atoms of carbon are in 7.11g of glucose?
To determine the number of carbon atoms in 7.11g of glucose, you first need to calculate the moles of glucose using its molar mass. The molar mass of glucose (C6H12O6) is 180.16 g/mol. Next, calculate the number of moles of carbon in one mole of glucose (6 moles). Finally, multiply the moles of glucose by the number of moles of carbon to find the total number of carbon atoms in 7.11g of glucose.
What mass of oxygen in grams is in 147.2 grams of glucose?
To determine the mass of oxygen in 147.2 grams of glucose (C6H12O6), we need to consider the molecular formula of glucose. For each mole of glucose, there are 6 moles of oxygen atoms. The molar mass of glucose is approximately 180.16 g/mol. Thus, the mass of oxygen in 147.2 grams of glucose would be (6/180.16) * 147.2 = approximately 4.88 grams.
What is the number of atoms contained in 5.72 grams of glucose?
To determine the number of atoms in 5.72 grams of glucose, you first need to calculate the number of moles of glucose using its molar mass. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Given that the molar mass of glucose is approximately 180.16 g/mol, you can then calculate the number of atoms in 5.72 grams of glucose.
If 154 grams of glucose are dissolved to yield one liter of solution what is the molarity of the solution?
Molarity = moles of solute/Liters of solution Find moles glucose, which is molecular formula------C6H12O6 154 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.8548 moles C6H12O6 Molarity = 0.8548 moles C6H12O6/1 Liter = 0.855 M glucose ---------------------------
How many grams of carbon dioxide would be produced if 45 g of C6H12O6 completely reacted with oxygen?
The balanced chemical equation for the combustion of glucose (C6H12O6) is: C6H12O6 + 6O2 -> 6CO2 + 6H2O. From the equation, we can see that 1 mol of C6H12O6 produces 6 mol of CO2. First, calculate the number of moles of C6H12O6 in 45 g. Then use the mole ratio to find the moles of CO2 produced, and finally convert that to grams.
What is the number of atoms in 18 gram of glucose?
To find the number of atoms in 18 grams of glucose, we first need to calculate the number of moles of glucose using its molar mass. The molar mass of glucose is approximately 180 grams/mol. Therefore, 18 grams of glucose is equal to 0.1 moles. Since 1 mole of glucose contains 6.022 x 10^23 atoms (Avogadro's number), 0.1 moles of glucose would contain 6.022 x 10^22 atoms.
What is the molarity of an aqueous solution containing 32.8 g of C6H12O6 in 1.0 L of solution?
Find moles of glucose. 32.8 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.18206 moles C6H12O6 Molarity = moles of solute/Liters of solution M = 0.18206 moles C6H12O6/1.0 L = 0.18 M C6H12O6
How many grams of carbon dioxide would be produced if 45 g of C6H12O6 competely reacted with oxygen?
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
What is the osmolarity of 5.5 percent glucose solution?
To calculate the osmolarity of a 5.5% glucose solution, first convert the percentage to grams per liter: 5.5% means 5.5 grams of glucose per 100 mL, which is 55 grams per liter. Glucose (C6H12O6) has a molar mass of approximately 180 g/mol, so 55 grams corresponds to about 0.306 moles per liter (55 g / 180 g/mol). Since glucose does not dissociate in solution, the osmolarity is equal to its molarity, which is approximately 0.306 osmoles per liter.
How many molecules are in 720 grams of C6H12O6?
To determine the number of molecules in 720 grams of C6H12O6 (glucose), you first need to calculate the number of moles present. The molar mass of glucose is 180.16 g/mol. Dividing 720 grams by the molar mass gives you 4 moles of C6H12O6. One mole of any substance contains Avogadro's number of molecules, which is approximately 6.022 x 10^23. Therefore, 4 moles of C6H12O6 would contain about 2.409 x 10^24 molecules.
How many grams of C6H12O6 are need to produce 8.57 millimoles?
Mol wt of C6H12O6 = 6*12 + 1*12 + 16*6 = 72+12+96 = 180 This implies that 180 grams of the compound is equivalent to 1 mole 1 mole = 180 grams => 1 millimole = 180 milligrams => 8.57 millimoles = 180*8.57= 1542.6 milligrams = 1.5426 grams
How many grams of carbon dioxide would be produced if 45 grams of glucose completely react with oxygen?
The chemical equation for the combustion of glucose is C6H12O6 + 6O2 -> 6CO2 + 6H2O. From this, we can see that 1 mole of glucose produces 6 moles of CO2. Therefore, 45 grams of glucose (which is approximately 0.25 moles) would produce 6 times that amount of CO2, which is about 90 grams.
