The reaction is with aluminium:
Fe2O3 + 2 Al = 2 Fe + Al2O3
Aluminum is produced by high-temperature electrolytic reduction of its oxide, alumina.
The chemical equation 2Al2O3 represents the reaction of two aluminum atoms with three oxygen atoms to form two molecules of aluminum oxide. This equation shows that for every two moles of aluminum, three moles of oxygen are required to form two moles of aluminum oxide.
The unbalanced equation for the reaction of barium oxide (BaO), calcium oxide (CaO), and strontium oxide (SrO) with aluminum (Al) is: BaO + CaO + SrO + Al -> Ba + Ca + Sr + Al2O3
The chemical equation for the reaction between barium oxide, calcium oxide, and strontium oxide with aluminum is: 3BaO + 2Al → Al₂O₃ + 3Ba CaO + 2Al → Al₂O₃ + Ca SrO + 2Al → Al₂O₃ + Sr
When manganese dioxide is heated with aluminium powder, the following reaction takes place: These displacement reactions are highly exothermic. The amount of heat evolved is so large that the metals are produced in the molten state. On the other hand when manganese is heated with aluminum oxide no reaction takes place as aluminum is more reactive than manganese and is placed higher in the activity series.
The balanced equation for aluminum reacting with iron(II) oxide to produce aluminum oxide and iron is: 2Al + FeO -> Al2O3 + 2Fe.
The half equation for the reduction of copper oxide by carbon is: CuO + C -> Cu + CO
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO → 3Cu + Al2O3. This reaction produces copper and aluminum oxide.
The balanced equation for the decomposition of aluminum oxide is: 2Al2O3(s) → 4Al(s) + 3O2(g)
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO -> 3Cu + Al2O3.
The word equation for aluminum forming its protective layer is: Aluminum + Oxygen → Aluminum oxide.
Aluminum is produced by high-temperature electrolytic reduction of its oxide, alumina.
The chemical equation 2Al2O3 represents the reaction of two aluminum atoms with three oxygen atoms to form two molecules of aluminum oxide. This equation shows that for every two moles of aluminum, three moles of oxygen are required to form two moles of aluminum oxide.
The unbalanced equation for the reaction of barium oxide (BaO), calcium oxide (CaO), and strontium oxide (SrO) with aluminum (Al) is: BaO + CaO + SrO + Al -> Ba + Ca + Sr + Al2O3
The balanced equation for the reaction between aluminum and iron (III) oxide to form aluminum oxide and iron is: 2Al + Fe2O3 → Al2O3 + 2Fe
2Al2O3 --> 4Al + 3O2
I am actually very, very good at physics, and I am quite, very good at chemistry. So the Equation is: Al + O = AlO2 The Answer is AlO2