The law relating all three is known as the Combined Gas Law, and follows the formula V1P1/T1=V2P2/T2.
The combined gas law states that P1V1/T1 = P2V2/T2. Note there are three variable, namely P(pressure), V(volume) and T(temperature). Thus, there can be no single relevant graph. One could have a graph of P vs. V or P vs T for example, but not a graph including all three variables.
To find the original volume of gas, you can use the combined gas law equation: (P1V1)/T1 = (P2V2)/T2. Plug in the given values to solve for the original volume, where P1 = 135 kPa, V1 = 575 L, T1 = 295 K, P2 = 105 kPa, and T2 = 270 K. Solving for V1 will give you the original volume of the gas.
Using the combined gas law (P1V1/T1 = P2V2/T2), we can calculate the new volume of the oxygen gas sample at 600K. Given P1V1/T1 = P2V2/T2, we have P1 = P2 (pressure is constant), V1 = 150 mL, T1 = 300K, and T2 = 600K. Plugging in these values, we get V2 = (P1 * V1 * T2) / (T1) = (1 * 150 * 600) / (300) = 300 mL. So, the new volume of the oxygen gas sample at 600K would be 300 milliliters.
An experimental gas law is the Charles Law. The formula used is original volume/original temperature= new volume/new temperature. The law describes expansion of gases with heat.
The general representation of the combined gas law is P1V1/T1 = P2V2/T2
The Combined Gas Law relates pressure (P), volume (V) and temperature (T). The appropriate SI units are P in atm, V in liters, and T in degrees Kelvin. The Combined Gas Law equation is (P1*V1)/T1 = (P2V2)/T2. Isolating for V2 the equation then becomes (P1V1T2)/(T1P2) = V2
This question refers to the combined gas law: (P1V1)/T1=(P2V2)/T2, where P is pressure, V is volume, and T is temperature in Kelvins.To solve for T1, rearrange the equation to isolate T1.T1=(P1V1T2)/(P2V2)
The law relating all three is known as the Combined Gas Law, and follows the formula V1P1/T1=V2P2/T2.
Well, pressure has to be kept constant and so does the mass of the gas with Charles's Law. Charles's Law--V1/T1=V2/T2--can be derived from the Combined Gas Law--V1xP1/T1=V2xP2/T2--by keeping the pressure constant which in turn cancels out the pressure in the Combined Gas Law leaving you with Charles's Law.
Boyle' Law P1V1 = P2V2 Charles' Law V1 / T1 = V2 / T2 Gay-Lussac's Law P1 ÷ T1 = P2 ÷ T2 The Combined Gas LawP1V1 / T1 = P2V2 / T2 The Ideal Gas Law PV=nRT KEY: P = pressure V = volume T = temperature R = 0.0821atm*L/mol*K n = number of mole of gas
Gay-Lussac's law. P1/T1 = P2/T2
Well, pressure has to be kept constant and so does the mass of the gas with Charles's Law. Charles's Law--V1/T1=V2/T2--can be derived from the Combined Gas Law--V1xP1/T1=V2xP2/T2--by keeping the pressure constant which in turn cancels out the pressure in the Combined Gas Law leaving you with Charles's Law. Hope that helps you!
The combined gas law deals with pressure, temperature, and volume. If you are given all three and then you are asked to find a variable in different conditions, then use the combined gas law.However, if you are given or are trying to find moles, then use the ideal gas law.
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To find the pressure of the nitrogen gas in the second flask, you can use the combined gas law equation: P1V1/T1 = P2V2/T2, where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature. Plug in the given values to find the final pressure of nitrogen in the second flask.
The combined gas law states that P1V1/T1 = P2V2/T2. Note there are three variable, namely P(pressure), V(volume) and T(temperature). Thus, there can be no single relevant graph. One could have a graph of P vs. V or P vs T for example, but not a graph including all three variables.