according to old concept of valency ,valency of an element= 2xno. of oxygen atoms.here 1atom of N combines with 5/2 atom of O.thus covalency of N is 5
To calculate the mass of 3.97x10^21 molecules of dinitrogen tetraoxide, you first need to find the molar mass of dinitrogen tetraoxide (N2O4), which is about 92.02 g/mol. Then you can use Avogadro's number (6.022x10^23 molecules/mol) to convert molecules to moles and then multiply by the molar mass to find the mass.
The length of nitrogen-to-nitrogen bond is approx. 100 pm.
The percentage of nitrogen in pure, dry ,standard air is 78,084 % (by volume).
The lowest concentration of nitrogen can be found in the urine when it is first produced. As it accumulates in the bladder, so does the overall concentration of nitrogen.
To find the number of moles of nitrogen in a 35.0g sample, you need to divide the mass of the sample by the molar mass of nitrogen. The molar mass of nitrogen is approximately 14.01 g/mol. Therefore, 35.0g / 14.01 g/mol = approximately 2.5 moles of nitrogen.
Dinitrogen hexahydrogen. Though you're unlikely to find it in nature, as the bonding of nitrogen to itself does not leave the 6 valence electrons necessary for the hydrogen molecules to also bond and form the compound.
Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.
Using the stoichiometry of the balanced chemical equation, we find that 5 moles of oxygen gas will produce 2 moles of dinitrogen pentoxide gas. At STP (standard temperature and pressure, 0 degrees Celsius and 1 atm pressure), 1 mole of ideal gas occupies 22.4 L. So, first calculate the number of moles of oxygen gas from the given volume of 500 ml using the ideal gas law. Then, use the stoichiometry of the balanced chemical equation to determine the volume of dinitrogen pentoxide gas produced (in liters) at STP.
This compound is dinitrogen pentachloride.
To find the number of molecules in 1296 g of dinitrogen pentoxide (N2O5), first calculate the molar mass of N2O5 which is 108 g/mol. Then, divide the given mass by the molar mass to get the number of moles (12 moles). Finally, use Avogadro's constant (6.022 x 10^23) to convert moles to molecules, giving approximately 7.2 x 10^23 molecules.
To calculate the mass of 3.97x10^21 molecules of dinitrogen tetraoxide, you first need to find the molar mass of dinitrogen tetraoxide (N2O4), which is about 92.02 g/mol. Then you can use Avogadro's number (6.022x10^23 molecules/mol) to convert molecules to moles and then multiply by the molar mass to find the mass.
i think you can find nitrogen in a hot air ballon
The length of nitrogen-to-nitrogen bond is approx. 100 pm.
The air in your house contain 78,05 nitrogen !
Our atmosphere is made up of 78 % nitrogen.
Why does atmospheric nitrogen need to be converted?
Open Your Eyes and you'll find it..