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If Mercury has an average distance to the sun of 0.39 AU in to complete sentences explain how to calculate the orbital period?
To calculate the orbital period of Mercury, you can use Kepler's Third Law of Planetary Motion, which states that the square of the orbital period (P) of a planet is directly proportional to the cube of the semi-major axis (a) of its orbit. The formula is ( P^2 = a^3 ), where P is the period in Earth years and a is the average distance from the sun in astronomical units (AU). For Mercury, you would substitute ( a = 0.39 ) AU into the equation, yielding ( P^2 = (0.39)^3 ), and then take the square root to find the orbital period. This results in an approximate orbital period of 0.24 Earth years, or about 88 Earth days.
How do you find the orbital period in earth years of a periodic comet if the furtherest from sun is 31.5 astronomical units while the closest is 0.5 astronomical units?
You can find the major axis, 0.5+31.5 or 32 AU. The semimajor axis is half that, 16 AU. Then you can use Keplers 3rd law to calculate the period, which is 161.5 or 64 years.
What Kepler's law to find Jupiter and period?
Kepler's Third Law states that the square of the orbital period of a planet (T) is directly proportional to the cube of the semi-major axis of its orbit (a), expressed as ( T^2 \propto a^3 ). For Jupiter, which has an average distance from the Sun of about 5.2 astronomical units (AU), this law can be used to calculate its orbital period. By applying the formula, one finds that Jupiter's orbital period is approximately 11.86 Earth years. This relationship helps to understand the motion of planets within our solar system.
Uranus requires 84 years to circle the sun Find Uranus' orbital radius as a multiple of Earth's orbital radius?
Uranus' orbital radius is about 19.22 times the average distance from Earth to the Sun (1 astronomical unit). This makes Uranus' average distance to the Sun approximately 19.22 astronomical units.
How do you find the number revolution days of each planet?
To find the number of revolution days of a planet, you can use the formula: revolution days = orbital period / rotation period. The orbital period is how long it takes for the planet to complete one orbit around the sun, while the rotation period is how long it takes for the planet to rotate on its axis. This formula will give you the number of days it takes for the planet to complete one full rotation around its axis.
If Mercury has an average distance to the sun of 0.39 AU in to complete sentences explain how to calculate the orbital period?
To calculate the orbital period of Mercury, you can use Kepler's Third Law of Planetary Motion, which states that the square of the orbital period (P) of a planet is directly proportional to the cube of the semi-major axis (a) of its orbit. The formula is ( P^2 = a^3 ), where P is the period in Earth years and a is the average distance from the sun in astronomical units (AU). For Mercury, you would substitute ( a = 0.39 ) AU into the equation, yielding ( P^2 = (0.39)^3 ), and then take the square root to find the orbital period. This results in an approximate orbital period of 0.24 Earth years, or about 88 Earth days.
If a planet has an average distance from the Sun of 9.1 AU, what is its orbital period SHOW YOUR WORK?
To calculate the orbital period of a planet with an average distance from the Sun of 9.1 Astronomical Units (AU), we use Kepler's Third Law of Planetary Motion: P^2 = a^3. Given: a = 9.1 AU Substitute the value of 'a' into Kepler's Third Law to find the orbital period, P: P^2 = (9.1)^3 P^2 = 753.571 AU^3 To find the orbital period P, take the square root of both sides of the equation: P = √753.571 P ≈ 27.45 years Conclusion: A planet with an average distance of 9.1 AU from the Sun has an estimated orbital period of approximately 27.45 Earth years.
How do you find the orbital period in earth years of a periodic comet if the furtherest from sun is 31.5 astronomical units while the closest is 0.5 astronomical units?
You can find the major axis, 0.5+31.5 or 32 AU. The semimajor axis is half that, 16 AU. Then you can use Keplers 3rd law to calculate the period, which is 161.5 or 64 years.
What Kepler's law to find Jupiter and period?
Kepler's Third Law states that the square of the orbital period of a planet (T) is directly proportional to the cube of the semi-major axis of its orbit (a), expressed as ( T^2 \propto a^3 ). For Jupiter, which has an average distance from the Sun of about 5.2 astronomical units (AU), this law can be used to calculate its orbital period. By applying the formula, one finds that Jupiter's orbital period is approximately 11.86 Earth years. This relationship helps to understand the motion of planets within our solar system.
Uranus requires 84 years to circle the sun Find Uranus' orbital radius as a multiple of Earth's orbital radius?
Uranus' orbital radius is about 19.22 times the average distance from Earth to the Sun (1 astronomical unit). This makes Uranus' average distance to the Sun approximately 19.22 astronomical units.
How to calculate the orbital period of a planet?
To calculate the orbital period of a planet, you can use Kepler's third law of planetary motion. The formula is T2 (42 r3) / (G M), where T is the orbital period, r is the average distance from the planet to the sun, G is the gravitational constant, and M is the mass of the sun. Simply plug in the values for r and M to find the orbital period of the planet.
What must you know in order to find out a planets period of revolution?
Orbital information. You need to know the size of the "semi-major axis". Then you can calculate the orbital period, using Kepler's Third Law.
A comet moves in an elliptical orbit around the sun its distance from the sun varies between 1 AU and 7 AU Calculate its orbital period?
Major axis of mentioned comet has length of 8 AU (1 AU at perihelion plus 7 AU at apohelion on the opposite side of Sun). According to Kepler's third law, the square of orbital period is directly proportional to cube of the orbit's major axis. When using astronomical units for distance and sidereal years for time, this simplifies to: T2 = a3, where T - orbital period a - length of major axis We can then calculate that T for a = 8 AU is about 22.62 years.
How can one calculate the orbital period using the semi-major axis?
To calculate the orbital period using the semi-major axis, you can use Kepler's third law of planetary motion. The formula is T2 (42 / G(M1 M2)) a3, where T is the orbital period in seconds, G is the gravitational constant, M1 and M2 are the masses of the two objects in the orbit, and a is the semi-major axis of the orbit. Simply plug in the values for G, M1, M2, and a to find the orbital period.
What is Jupiters speed of travel in mph?
i am sorry i could not find the answer to your question but this might help you:A Jupiter completes an orbits every 11.86 years. This is two-fifths the orbital period of Saturn, forming a 5:2 orbital resonance between the two largest planets in the Solar System.here is another thing that might help you:Jupiter completes one orbit in 4,333 Earth days, or almost 12 Earth years.Here is the source that i looked at ( might come in handy for you)www.nasa.gov
How can you find out the distance between the Sun and Jupiter Given is Jupiter's year is 11.86 Earth years and the distance between the Sun and the Earth is 1.5x1011 meters?
Using Kepler's 3rd law of motion: T2/a3=const. T - orbital period a - distance to the Sun For Earth: T2/a3= 12/(1.5x1011)3=2.96x10-34 (11.86)2/a3=2.96x10-34 . . . a=780,095,402,531.93 meters = 5.2 AU
How do you find the period of revolution of a planet?
You have to watch it and record its position every night until it has travelled right round the ecliptic until it gets back to where you first saw it. The time taken is called the synodic period. Then you have to allow for the fact that the Earth has been going round at the same time. That gives the true orbital period.
