An 11 M KOH solution indicates there are 11 moles of KOH per liter of water. 1 mole of KOH has a volume of 27.4 mL, so to account for the added volume it is necessary to add 15.75 moles of KOH per liter of water, or 884 grams per liter.
1 cm is .01m so 600cm*.01m = 6m =] -ray
When KOH reacts with HCl, these products are formed. This is a neutralization reaction. KOH is a base while HCl is an acid.
The answer is 12,831 g KOH.
because KOH is hygroscopic
The elements found in KOH are potassium, oxygen and hydrogen.
.01m = 1cm
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1 cm is .01m so 600cm*.01m = 6m =] -ray
When KOH reacts with HCl, these products are formed. This is a neutralization reaction. KOH is a base while HCl is an acid.
i have Audi 01N and use it
Koh-Kee-Ree-Koh
To prepare 20 wt% KOH solution from 85% KOH pellets, you would mix a specific amount of the 85% KOH pellets with water to dilute it to the desired concentration. For example, to make 100g of 20% solution, you would mix 23.5g of the 85% KOH pellets with 76.5g of water. Be sure to handle KOH with care as it is caustic and can cause burns.
To prepare a 30% methanolic KOH solution, you would mix 30g of KOH with enough methanol to make a total solution volume of 100mL. This would result in a solution where 30% of the total weight comes from KOH. Be cautious when handling KOH as it is a caustic substance and should be handled with appropriate precautions.
0.800 M KOH (1mol/2.5L)(56.1g KOH/1mol)It's set up stoichiometrically, but hard to show that here... 0.800 M KOH / 2.5 L x 56.1gYour answer should come out 17.952 g KOH. If you're following sig figs, then your answer should come out 18. g KOH
I assume you mean 7.25 M KOH, but the process is the same anyway.Molarity = moles of solute/Liters of solution ( 400 ml = 0.4 Liters )7.25 M KOH = X moles KOH/0.4 Liters= 2.9 moles KOH (56.108 grams/1 mole KOH)= 163 grams potassium hydroxide needed===============================
A solution that is refered to as a percentage of something (like potassium hydroxide, KOH) refers to the mass of the solute compared to the total solution, so a 5% KOH solution would be 5g KOH + 95g H2O, and the 5g KOH would be 5% of the 100g total of the solution.
1cm = .01m therefore 1cm2 = .01x.01 = .0001m2