The initial total pressure is 1.0 ATM + 2.0 ATM = 3.0 ATM. Therefore, 6.0 ATM - 3.0 ATM = 3.0 ATM of helium was added to the tank. Hence, the partial pressure of helium in the tank is 3.0 ATM.
To find the pressure of gas B, you can use Dalton's Law of Partial Pressures, which states that the total pressure is the sum of the partial pressures of individual gases. Given that the total pressure is 1.20 ATM and the partial pressure of gas A is 0.75 ATM, you can calculate the pressure of gas B as follows: Pressure of gas B = Total pressure - Pressure of gas A = 1.20 ATM - 0.75 ATM = 0.45 ATM. Thus, the pressure of gas B is 0.45 ATM.
The correct pressure in kPa for 1.54 ATM is 156.6 kPa. This conversion is based on the fact that 1 ATM is equal to 101.3 kPa.
The partial pressure of SO4 in a bottle of NO2, CO2, and SO2, is 7.32 atm.
Using the combined gas law, we can calculate the new pressure. The initial conditions are V1 = 900 mL, P1 = 2.50 ATM, and T1 = 298 K. The final conditions are V2 = 450 mL, T2 = 336 K. Using P1V1/T1 = P2V2/T2, we can solve for the new pressure, which is around 3.33 ATM.
To find the new pressure, we can use Boyle's Law, which states that pressure and volume are inversely proportional at constant temperature. By applying the formula P1V1 = P2V2, where P1 = 1.5 ATM, V1 = 5.6 L, and V2 = 4.8 L, we can solve for P2. Thus, the new pressure would be 1.75 ATM.
To decrease the pressure of the nitrogen to 1.0 atm, you would need to increase the volume. Use the combined gas law (P1V1/T1 = P2V2/T2) to calculate the new volume required. Given that the initial pressure is 3.2 atm, initial volume is 2.0 liters, and final pressure is 1.0 atm, you can rearrange the equation to solve for V2.
Using the ideal gas law, we can calculate the new pressure of the gas. The initial pressure is 1 atm, the initial volume is 1.00 L, and the final volume is 0.473 L. By applying the formula P1V1 = P2V2, we can solve for the new pressure of the gas after compression.
1.54 atm
1.54 atm
The total pressure of the mixed gases will be 5 ATM. The partial pressure of each gas will remain the same as their individual pressures before mixing, so the partial pressure for the gas originally at 2 ATM will remain at 2 ATM, and the gas originally at 3 ATM will remain at 3 ATM.
The initial total pressure is 1.0 ATM + 2.0 ATM = 3.0 ATM. Therefore, 6.0 ATM - 3.0 ATM = 3.0 ATM of helium was added to the tank. Hence, the partial pressure of helium in the tank is 3.0 ATM.
1.54atm
A. An increase in pressure from 2 ATM to 3 ATM will result in a decrease in volume of gas. B. An increase in pressure from 3 ATM to 4 ATM will result in a decrease in volume of gas. C. A decrease in pressure from 4 ATM to 1 ATM will result in an increase in volume of gas. D. An increase in pressure from 1 ATM to 3 ATM will result in a decrease in volume of gas.
2 atm + 3 atm
1.54 atm
1.54 atm