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How does the oxidation state of Na change in the following reaction?

In the reaction where Na is oxidized to Na+ in a chemical reaction, the oxidation state of Na changes from 0 to +1. This means that Na loses one electron and is oxidized.


How does the oxidation state of Na change in the following reaction Li NaOH LiOH Na?

The oxidation state of Na changes from 0 in Na to +1 in NaOH and then back to 0 in Na in the reaction. Na starts as a neutral metal atom, gains an electron in NaOH to have an oxidation state of +1, and then loses that electron to return to its neutral state in the final product.


How does the oxidation state of Li change in the following reaction Li(s) NaOH(aq)-LiOH(aq) Na(s)?

Li(0) to Li(+1) when Na(+1) transforms to Na(0); 1 electron is transferred from Li(0) to Na(+1) in this redox reaction


What is the oxidation state of NaBrO3?

The oxidation states for Na, Br, and O are +1, +5, and -2, respectively. In NaBrO3, there is 1 Na, 1 Br, and 3 O atoms, leading to a total charge of 0. Thus, the oxidation state of NaBrO3 is +5 to balance the charge.


How does the oxidation satae of O change in the following reaction L(s) plus NaOH(aq) plus Na(s)?

Not sure what L(s) is supposed to be, but regardless, the oxidation state of Na changes from 1+ in NaOH to zero in Na(s).


How does the oxidation state of 0 change in the following reaction?

The oxidation state of an element with oxidation state 0 cannot change, as it already has a balance of electrons.


What is the oxidation number of Na in Na2O2?

+1 for each Na -1 for oxygen (as it is peroxide)


What is the oxidation state of na2so4?

In Na2SO4, the oxidation state of sodium (Na) is +1, the oxidation state of sulfur (S) is +6, and the oxidation state of oxygen (O) is -2. To calculate the oxidation state of the whole compound, you can use the rule that the sum of the oxidation states in a neutral compound is zero, so in this case it would be +1*2 + (-2)*4 = 0.


What is the oxidation number of H in the compound NaHSO4?

The oxidation number of H in NaHSO4 is +1. In this compound, Na has an oxidation state of +1, S has an oxidation state of +6, and O has an oxidation state of -2. By adding up the oxidation states and solving for H, it is determined to be +1.


What is the oxidation state of Sodium Nitrate?

Sodium Oxide, or NaOH, has no oxidation state. It has a charge, which is zero. The elements that make up NaOH, however, do have oxidation states. The oxidation state of sodium (Na) is +1, and it will forever be +1 because it is impossible for it to be anything else, no matter what situation. The same applies for Hydrogen. Oxygen has an oxidation state of -2, and almost always will have an oxidation state of -2. There is one notable exception: H2O2. In this case, since the total charge of the compound is neutral and the oxidation state of Hydrogen must be +1 and, seeing as there are two hydrogens, bringing the overall charge up to 2, the oxidation state of oxygen must be -1. If it was -2, then the molecule would have an overall charge of -2.


What is the oxidation number in NaNO3?

The oxidation number of Na in NaNO3 is +1, since Na typically has a +1 oxidation state in compounds. The oxidation number of N in NO3 is +5, since oxygen is usually assigned a -2 oxidation state and there are three oxygen atoms bonded to nitrogen in NO3.


What is the oxidation state of NA in NA2O2 and K in KO2?

The oxidation state of Na in Na2O2 is +1, as each Na atom carries a +1 charge while the O atoms carry a -1 charge. In KO2, the oxidation state of K is +1, similar to Na2O2, as each K atom carries a +1 charge while the O atoms carry a -1/2 charge.