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How many Ag atoms are there in a 88.1 gram sample of Ag?
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
How many moles of silver (Ag) are present in a sample of 3.8 10 to the power of twenty four atoms Ag?
The answer is 6,31 moles Ag.
How many moles of Ag in 8.9 x 1024 atoms Ag?
If you meant 8.9 * 10^24, then there are 14.78 moles. 8.9 e24 (# of atoms) / 6.02 e23 (# of atoms in a mole) = 14.78 (# of moles)
How many moles of Ag contains 4.591025 atom of Ag?
Quite a few moles of silver if you mean, 4.59 X 10^25 atoms of silver. 4.59 X 10^25 atoms silver (1 mole Ag/6.022 X 10^23) = 76.2 moles of silver ----------------------------
Number of moles and number of atoms in a 214 gram sample of silver?
According to the periodic table, silver (Ag) has an atomic mass of about 108 grams per mole. If you have 802 grams, set up a direct proportion where 108/1=802/x and solve for x. You get about 7.43 moles of silver.
How many Ag atoms are there in a 88.1 gram sample of Ag?
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
How many ag atoms are there in 0.0001 grams of Ag.Molar mass of Ag is 108 gram per mole?
To find the number of atoms in 0.0001 grams of silver (Ag), first determine the number of moles in 0.0001 grams using the molar mass of Ag (108 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, 0.0001 g of Ag is equal to 6.94 x 10^16 Ag atoms.
How many atoms are in 1 mole of Ag?
There are 6.022 x 10^23 atoms in 1 mole of silver (Ag) as per Avogadro's number.
How many atoms are there in one gram of hydrogen?
It depends on the atomic mass of a substance. To find out, divide the 1 by the atomic mass of the element (found on the periodic table), then multiply by 6.02*1023. Ag=(1/Am)*6.02*1023 Where Am=atomic mass of the element, and Ag=the number of atoms in a gram.
How many moles of Ag contain 4.4910e23 atoms Ag?
To find the number of moles, we first need to calculate the number of moles of Ag atoms using Avogadro's number (6.022 x 10^23 atoms/mol). Number of moles = 4.4910e23 atoms Ag / (6.022 x 10^23 atoms/mol) ≈ 0.746 moles of Ag.
How many atoms are in silver phosphate?
Silver phosphate is Ag3PO4It has 3 Ag atoms + 1 P atom + 4 O atoms = 3+1+4 = 8atoms per molecule Ag3PO4
How many grams are therein 2.31024 atoms of silver?
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
How many moles of silver (Ag) are present in a sample of 3.8 10 to the power of twenty four atoms Ag?
The answer is 6,31 moles Ag.
How many moles of Ag contains 4.59x10 to the power of 25 atoms of Ag?
76.2 mol Ag
How many mols are there in 5.42x10 to the 24 of atoms Ag?
5.42 X 10^24 atoms silver ( 1mole Ag/6.022 X 10^23) = 9.00 moles of silver
How many moles of Ag in 8.9 x 1024 atoms Ag?
If you meant 8.9 * 10^24, then there are 14.78 moles. 8.9 e24 (# of atoms) / 6.02 e23 (# of atoms in a mole) = 14.78 (# of moles)
How many atoms are in 1.45 g of Ag?
To find the number of atoms in 1.45 g of Ag (silver), you first need to determine the molar mass of Ag. The atomic weight of silver is 107.87 g/mol. Next, you would convert the mass given (1.45 g) into moles, then use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms. The calculation would look like this: 1.45 g Ag * (1 mol Ag / 107.87 g Ag) * (6.022 x 10^23 atoms / 1 mol) = number of Ag atoms.
