How many atoms are in 1.45 g of Ag?

Answer 1

Convert 1 gram Fe to moles by dividing by molecular weight, in this case: 55.8 g/mol.

So 1 gram = 1/55.8 or 0.0179 moles of Fe. 1 mole of any substance contains Avogadro's number of atoms or 6.022e23. So multiply 0.0179 by 6.022e23 to get:

1.079*1022 atoms of Fe (iron)

Answer 2

To find the number of atoms in 1.45 g of Ag (silver), you first need to determine the molar mass of Ag. The atomic weight of silver is 107.87 g/mol. Next, you would convert the mass given (1.45 g) into moles, then use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms. The calculation would look like this:

1.45 g Ag * (1 mol Ag / 107.87 g Ag) * (6.022 x 10^23 atoms / 1 mol) = number of Ag atoms.

Answer 3

Iron is atomic number 26. Its Atomic Mass is 55.847.

0.45g * 1 mol/55.847g * 6.023*10^23 atoms/mol = 4853170268770032409977.2592977241 atoms.

Answer 4

This is one mole of iron atoms, and there are 6.022045 x 1023 atoms in a mole.

Answer 5

5,0 grams Fe contains 5/55.85(Mw Fe) = 0,08952 mole, times Avogadro's constant (6,022 x 10^23) is 5,39 x 10^22 atoms.

Answer 6

It is 1 mole, which is 6.022x1023 atoms (avagadro's number of atoms)

Answer 7

There are 3.8 x 10^20 atoms in 1.45 g of Ag which is silver.