Convert 1 gram Fe to moles by dividing by molecular weight, in this case: 55.8 g/mol.
So 1 gram = 1/55.8 or 0.0179 moles of Fe. 1 mole of any substance contains Avogadro's number of atoms or 6.022e23. So multiply 0.0179 by 6.022e23 to get:
1.079*1022 atoms of Fe (iron)
Iron is atomic number 26. Its Atomic Mass is 55.847.
0.45g * 1 mol/55.847g * 6.023*10^23 atoms/mol = 4853170268770032409977.2592977241 atoms.
This is one mole of iron atoms, and there are 6.022045 x 1023 atoms in a mole.
5,0 grams Fe contains 5/55.85(Mw Fe) = 0,08952 mole, times Avogadro's constant (6,022 x 10^23) is 5,39 x 10^22 atoms.
It is 1 mole, which is 6.022x1023 atoms (avagadro's number of atoms)
There are 3.8 x 10^20 atoms in 1.45 g of Ag which is silver.
3.68 grams silver (1 mole Ag/107.9 grams)(6.022 X 10^23/1 mole Ag) = 2.05 X 10^22 atoms of silver -----------------------------------------
0,263 mole of Ag is equal to 28,37 g.
The number of atoms of lead is 6,68.10e23.
1 atom of silver (Ag)= 107.87 amu 1 mole of a substance is 6.022 x 1023 of that substance. 1 MOLE of silver (Ag)= 107.87 grams So, in the three step formula: 1 atom Ag x 1 mole Ag/6.022 x 1023 atoms Ag ≈ 1.660577881 x 10-24 Mole Ag 1.660577881 x10-24 Mole Ag x 107.87 g Ag/ 1 mole Ag ≈ 1.79126536 x 10-22 g. Ag Or, to conserve significant figures, 1.7913 x 10-22 g. Ag (because 1 mole is definite, we don't count its significant figures
149 g of calcium contain 22,39.10e23 atoms.
The atomic weight of silver is 107,8682 g/molTo convert grams to moles:moles Ag=35,5 g Ag1 mol= 0,329 mol Ag107,8682 g
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
3.68 grams silver (1 mole Ag/107.9 grams)(6.022 X 10^23/1 mole Ag) = 2.05 X 10^22 atoms of silver -----------------------------------------
The equivalent of 68,3 g Ag is 0,633 moles.
Answer: 145 lb = 65,770.893 g
0,263 mole of Ag is equal to 28,37 g.
[155 (g Ag2O) / 231.8 (g Ag2O/mol Ag2O)] * 2 (mol Ag/mol Ag2O) == 310/231.8 mol Ag = 1.337 == 1.34 mole Ag
The number of atoms of lead is 6,68.10e23.
1 atom of silver (Ag)= 107.87 amu 1 mole of a substance is 6.022 x 1023 of that substance. 1 MOLE of silver (Ag)= 107.87 grams So, in the three step formula: 1 atom Ag x 1 mole Ag/6.022 x 1023 atoms Ag ≈ 1.660577881 x 10-24 Mole Ag 1.660577881 x10-24 Mole Ag x 107.87 g Ag/ 1 mole Ag ≈ 1.79126536 x 10-22 g. Ag Or, to conserve significant figures, 1.7913 x 10-22 g. Ag (because 1 mole is definite, we don't count its significant figures
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
149 g of calcium contain 22,39.10e23 atoms.
3.4g AgNO3 @ 107.9 g Ag / 169.9 g/mol AgNO3 = 2.159 g Ag youir answer ( 2 sig figs) : 2.2 grams of Ag