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How many moles in 0.0688g Ag CL?
To find the number of moles in 0.0688g AgCl, first calculate the molar mass of AgCl. It is 143.32 g/mol. Then divide the given mass (0.0688g) by the molar mass to get the number of moles. This gives you approximately 0.00048 moles of AgCl.
How many grams of silver are in 0.263 mole of Ag?
To convert moles to grams, you need to use the molar mass of silver (Ag), which is 107.87 g/mol. Multiply the number of moles by the molar mass to find the grams. Therefore, 0.263 moles of Ag is equivalent to 0.263 moles * 107.87 g/mol ≈ 28.4 grams of silver.
What is the mass in grams of silver found in 0.263 mol of Ag?
The amount of moles is also defined as n = m/M, wheren - amount of moles,m - the mass of the substance,M - the atomic mass of the substance (Ag - 107.8682 g/mol), thereforem = n×M = 0.263×107.8682 = 28,369 grams of Ag.
How many moles of silver are present in 32.46g of AgNO3?
To find the number of moles of silver in 32.46g of AgNO3, first calculate the molar mass of AgNO3 (169.87 g/mol). Then, divide the given mass by the molar mass to find the number of moles (32.46g / 169.87 g/mol ≈ 0.191 moles). Since there is one mole of Ag in one mole of AgNO3, there are 0.191 moles of silver present.
How many grams of silver can be produced from the reaction of 92.8 g of silver nitrate with 1.34 g of aluminum?
Oxidation-reduction reaction:Ag^+(aq) + Al(s) ===> Ag(s) + Al^3+ or looked at another way... 3AgNO3(aq) + Al(s) ===> Al(NO3)3(aq) + 3Ag(s) moles AgNO3 present = 92.8 g x 1 mole/170 g =0.546 moles moles Al present = 1.34 g x 1 mole/26.9 g = 0.0498 moles Al is limiting based on mole ratio of 3 AgNO3 : 1 Al moles Ag(s) produced = 0.0498 moles Al x 3 moles Ag/mole Al = 0.1494 moles Ag mass of Ag = 0.1494 moles Ag x 108 g/mole = 16.1 g Ag formed
What is the mass of 2.65 moles of Ag(s)?
The mass of 2,65 Ag moles is 285,85 g.
How many moles in 0.0688g Ag CL?
To find the number of moles in 0.0688g AgCl, first calculate the molar mass of AgCl. It is 143.32 g/mol. Then divide the given mass (0.0688g) by the molar mass to get the number of moles. This gives you approximately 0.00048 moles of AgCl.
How many grams of silver are in 0.263 mole of Ag?
To convert moles to grams, you need to use the molar mass of silver (Ag), which is 107.87 g/mol. Multiply the number of moles by the molar mass to find the grams. Therefore, 0.263 moles of Ag is equivalent to 0.263 moles * 107.87 g/mol ≈ 28.4 grams of silver.
What is the mass in grams of silver found in 0.263 mol of Ag?
The amount of moles is also defined as n = m/M, wheren - amount of moles,m - the mass of the substance,M - the atomic mass of the substance (Ag - 107.8682 g/mol), thereforem = n×M = 0.263×107.8682 = 28,369 grams of Ag.
How many moles are in 47.0 grams of Ag?
To find the number of moles in 47.0 grams of Ag (silver), divide the mass given by the molar mass of silver (107.87 g/mol). [ \text{Number of moles} = \frac{47.0 , \text{g}}{107.87 , \text{g/mol}} \approx 0.436 , \text{moles} ]
How many moles of silver (Ag) are equivalent to 68.3 g Ag?
The equivalent of 68,3 g Ag is 0,633 moles.
How many moles of silver are present in 32.46g of AgNO3?
To find the number of moles of silver in 32.46g of AgNO3, first calculate the molar mass of AgNO3 (169.87 g/mol). Then, divide the given mass by the molar mass to find the number of moles (32.46g / 169.87 g/mol ≈ 0.191 moles). Since there is one mole of Ag in one mole of AgNO3, there are 0.191 moles of silver present.
How many grams of silver can be produced from the reaction of 92.8 g of silver nitrate with 1.34 g of aluminum?
Oxidation-reduction reaction:Ag^+(aq) + Al(s) ===> Ag(s) + Al^3+ or looked at another way... 3AgNO3(aq) + Al(s) ===> Al(NO3)3(aq) + 3Ag(s) moles AgNO3 present = 92.8 g x 1 mole/170 g =0.546 moles moles Al present = 1.34 g x 1 mole/26.9 g = 0.0498 moles Al is limiting based on mole ratio of 3 AgNO3 : 1 Al moles Ag(s) produced = 0.0498 moles Al x 3 moles Ag/mole Al = 0.1494 moles Ag mass of Ag = 0.1494 moles Ag x 108 g/mole = 16.1 g Ag formed
Copper will react with silver nitrate to form copper nitrate and silver From this reaction 127.1 grams of copper will produce how many grams of silver?
The balanced equation for the reaction is: Cu + 2AgNO3 -> Cu(NO3)2 + 2Ag Calculate the molar mass of Cu and Ag (Cu = 63.55 g/mol, Ag = 107.87 g/mol). Using the molar ratio of Cu to Ag (1:2), convert the mass of Cu to moles, then use the molar ratio to find the moles of Ag produced. Finally, convert moles of Ag to grams using the molar mass of Ag to find the grams of silver produced.
How many grams of Ag can be formed from 5.50 grams of Ag2O in the equation 2Ag2O s 4Ag s O2 g?
Given 2Ag2O(s) --> 4Ag(s) + O2(g), and 5.50g of reactant, you get 5.5/232gmol-1 (molar mass reactant)=0.0237mol, times(2) (stoichiometric ratio)=0.0474mol Ag, times(108gmol-1) (atomic mass silver)=approx. 5.12g silver.
How many moles of silver (Ag) are present in a sample of 3.8 10 to the power of twenty four atoms Ag?
The answer is 6,31 moles Ag.
How many moles of Ag contain 4.4910e23 atoms Ag?
To find the number of moles, we first need to calculate the number of moles of Ag atoms using Avogadro's number (6.022 x 10^23 atoms/mol). Number of moles = 4.4910e23 atoms Ag / (6.022 x 10^23 atoms/mol) ≈ 0.746 moles of Ag.
