The Atomic Mass of Al is 27.0
Amount of Al in a 50g pure sample = 50/27.0 = 1.85mol
To determine the number of moles of N2 in 50g, you first need to find the molar mass of N2 (28.02 g/mol). Then, you divide the given mass (50g) by the molar mass to get the number of moles. In this case, 50g / 28.02 g/mol ≈ 1.79 moles of N2.
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
To determine how many moles of aluminum (Al) are produced from 20 moles of aluminum oxide (Al2O3), we need to use the balanced chemical equation for the reduction of Al2O3. The equation is: 2 Al2O3 → 4 Al + 3 O2. From this, we see that 2 moles of Al2O3 produce 4 moles of Al. Therefore, from 20 moles of Al2O3, we can calculate that 20 moles of Al2O3 would produce 40 moles of Al.
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
The answer is 3,375 moles oxygen.
To determine the number of moles of N2 in 50g, you first need to find the molar mass of N2 (28.02 g/mol). Then, you divide the given mass (50g) by the molar mass to get the number of moles. In this case, 50g / 28.02 g/mol ≈ 1.79 moles of N2.
To determine the number of moles in 50g of NaCl, you first need to find the molar mass of NaCl, which is approximately 58.44 g/mol. Then, you divide the given mass by the molar mass to find the number of moles. So, 50g of NaCl represents approximately 0.855 moles (50g / 58.44 g/mol = 0.855 mol).
To determine the number of moles in a 50g sample of estrogen, you need to know its molecular weight. The molecular weight of estrogen (specifically estradiol, a common form) is approximately 272.38 g/mol. Using the formula: moles = mass (g) / molar mass (g/mol), you can calculate the moles: 50g / 272.38 g/mol ≈ 0.183 moles of estrogen in the sample.
0.49038225061051505
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
To determine how many moles of aluminum (Al) are produced from 20 moles of aluminum oxide (Al2O3), we need to use the balanced chemical equation for the reduction of Al2O3. The equation is: 2 Al2O3 → 4 Al + 3 O2. From this, we see that 2 moles of Al2O3 produce 4 moles of Al. Therefore, from 20 moles of Al2O3, we can calculate that 20 moles of Al2O3 would produce 40 moles of Al.
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
A 50g sample of H2O contains approximately 2.78 x 10^24 molecules of water. This is calculated by first converting the mass to moles, then using Avogadro's number to determine the number of molecules present in that many moles of water.
The answer is 3,375 moles oxygen.
50g of what ?
Sounds like an acid metal reaction to produce hydrogen gas, so I will assume you meant hydrochloric acid. Complete reaction indicates aluminum is limiting and drives the reaction. 2Al + 6HCl --> 2AlCl3 + 3H2 3.0 moles Al (3 moles H2/2 moles Al) = 4.5 mole hydrogen gas produced =========================
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============