3.7x10^3 millimoles is 3.7 moles. To convert moles to atoms, multiply by avagadro's number. 3.7 x 6.022x10^23 is 2.22814x10^24 atoms.
4.0 moles Cu (6.022 X 1023/1 mole Cu) = 2.4 X 1024 atoms of copper ====================
Divide that number of atoms by 6.02x10^23 atoms/mole
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Copper nitrate molecule contain nine atoms.
7 atoms, like math, if in parenthesis multiple. 2 x 3 = 6 plus one atom of Ca for a total of 7 atoms.
There are 5 atoms in one molecule of Cu(OH)2, comprising one copper (Cu) atom, two oxygen (O) atoms, and two hydrogen (H) atoms.
Cu(NO3)2 has 9 atoms 1 Cu atom 2 N atoms 6 O atoms
Divide that number of atoms by 6.02x10^23 atoms/mole
4.0 moles Cu (6.022 X 1023/1 mole Cu) = 2.4 X 1024 atoms of copper ====================
1 mol Cu Atoms (6.02x10^23 atoms)
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There are 11 atoms in one formula unit of Cu(NO3)2: one copper atom (Cu), two nitrogen atoms (N), six oxygen atoms (O), and two nitrogen atoms (N) from the nitrate (NO3) group.
Copper nitrate molecule contain nine atoms.
7 atoms, like math, if in parenthesis multiple. 2 x 3 = 6 plus one atom of Ca for a total of 7 atoms.
There is no CuSO. If you mean CuSO4, it would be 6 atoms per formula unit; one Cu atom, one S atom, and 4 O atoms.
To calculate the number of Cu atoms in 85 mol, you need to use Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol. So, for 85 mol of Cu, the number of Cu atoms would be 85 mol x 6.022 x 10^23 atoms/mol = 5.12 x 10^25 Cu atoms.
3 types, Cu (Copper), Fe (Iron) and S(Sulfur)