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How many Cu atoms are present in 85mol?
To calculate the number of Cu atoms in 85 mol, you need to use Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol. So, for 85 mol of Cu, the number of Cu atoms would be 85 mol x 6.022 x 10^23 atoms/mol = 5.12 x 10^25 Cu atoms.
How many moles of Cu are in the 148 times 10 to the power 25 atoms?
15.8 moles Cu x 6.02x10^23 atoms/mole = 9.51x10^22 atoms. There are no molecules in the element Cu (copper). Molecules are found when there are two or more atoms bound together, such as in H2 gas or H2O, etc.
How many atoms in CuSO4.5H2O explain please?
Copper sulfate pentahydrate (CuSO4·5H2O) contains one copper (Cu) atom, one sulfur (S) atom, four oxygen (O) atoms, and ten hydrogen (H) atoms. So, in total, there are 16 atoms in one molecule of CuSO4·5H2O.
What is special about carbon atoms that they can make so many kinds of molecules?
Carbon atoms can be bonded together.
How many moles are of Cu are there in 3.0x1021 atoms?
The formula unit for copper is a single atom. Avogadro's Number is the number of atoms, formula units, or molecules per mole. (3.0 X 1021)/(6.022 X 1023) equals 5.0 X 10-3 moles, to the justified number of significant digits.
How many Cu atoms are present in 85mol?
To calculate the number of Cu atoms in 85 mol, you need to use Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol. So, for 85 mol of Cu, the number of Cu atoms would be 85 mol x 6.022 x 10^23 atoms/mol = 5.12 x 10^25 Cu atoms.
How many moles of Cu are in the 148 times 10 to the power 25 atoms?
15.8 moles Cu x 6.02x10^23 atoms/mole = 9.51x10^22 atoms. There are no molecules in the element Cu (copper). Molecules are found when there are two or more atoms bound together, such as in H2 gas or H2O, etc.
How do you balance CuCl Cl2 - CuCl2?
To balance the equation Cu + Cl2 → CuCl2, you need to make sure there are the same number of atoms on each side: 2 Cu atoms on the left, 2 Cl atoms in CuCl2, and 2 Cl atoms in Cl2. So, the balanced equation is Cu + Cl2 → CuCl2.
How many atoms of copper Cu are in a pure copper coin weighing 12.0 g?
Answer: 1.14x10^23 atoms Cu (12.0g Cu/63.55amu(g) Cu) Then take (Ans x 6.022x10^23) = 1.13712038x10^23 atoms Cu. Then I simplified it to 3 sig figs. = 1.14x10^23 atoms Cu Never forget your units and substance!
How many atoms in 2.6 mol cu?
2.6 * 6.022 * 10^23 atoms Explanation- 1 mol of anything has 6.022 * 10^23 units. So 2.6 mol has 2.6 times this number. Also Cu is monoatomic Note: * means multiplied; ^ means raised to the power
How many atoms in CuSO4.5H2O explain please?
Copper sulfate pentahydrate (CuSO4·5H2O) contains one copper (Cu) atom, one sulfur (S) atom, four oxygen (O) atoms, and ten hydrogen (H) atoms. So, in total, there are 16 atoms in one molecule of CuSO4·5H2O.
How many atoms are in cuSO3?
One copper, one sulphur and three oxygen. So total of five atoms
What is special about carbon atoms that they can make so many kinds of molecules?
Carbon atoms can be bonded together.
3.8 Liters is how many cu in?
To convert liters to cu in you have to multiply by 61.08. So,3.8 x 61.02 =231.876 cu in
How many nitrogen atoms are in 10.2 g of copper(II) nitrate?
There are 2 nitrogen atoms in 1 molecule of copper(II) nitrate (Cu(NO3)2). To find the number of nitrogen atoms in 10.2 g of Cu(NO3)2, you first need to calculate the number of moles of Cu(NO3)2 in 10.2 g, then use the mole ratio to find the number of nitrogen atoms. The molar mass of Cu(NO3)2 is 187.56 g/mol.
How many atoms in 1 cm3 of copper?
The density of copper (Cu) is about 8.92 g/cm3. So 1 cm3 of copper is about 8.92 g. Next find the number of moles in 8.92 g of copper by dividing by its molecular weight:8.92 g Cu / 63.54 g/mol Cu = 0.14038 mol CuBy definition 1 mol of any substance is Avogadro's number of atoms or, 6.022 x 10 23 atoms.So, 0.14038 mol Cu * [6.022x1023 atoms Cu / mol Cu] = 8.45x1022 atoms of Cu
How many Cu atoms are in the 0.0159 mol sample?
The molar mass of copper is approximately 63.5 g. To find how many of these are in our sample we must divide.0.0159/63.5 = 2.5 x 10 ^ -4 = 0.00025 moles. Each mole contains the Avogadro number of atoms, i.e. 6.023 x 10 ^ 23, so in total we have 0.00025x 6.023 x 10 ^ 23 = 1.51 x 10 ^ 20 atoms approximately.
