1 mole contains 6.023 times 10^23 atoms....so ......2 moles ...that would be 2 times 6.023 times 10^23 got it?
1.76 grams CO2 (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O2) = 4.82 X 10^22 atoms of oxygen gas
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
The balanced equation for the reaction must be given to determine the molar ratio between O2 and P2O5. Without that information, it is not possible to determine the exact number of moles of P2O5 produced from 8.00 moles of O2.
You use the Mole-to-Mole ratio. If the equation is 2CH4 + 2H2O = 6H2 + 2CO, then you would start with your given, 8.0 mol CO and multiply that with your mol-to-mol ratio which is (2mol CO/ 2 mol CH4). Your answer will be 8.0 mol.
1 mole O vs 0.5 mole O2 A mole of anything is 6.022 X 10^23, Avogadro's number. So one mole of single oxygen atoms is Avogadro's number while 1/2 mole of one oxygen atom is 3.011 X 10^23. So you have 1/2 mole of two oxygen atoms. 3.011 X 10^23 + 3.011 X 10^23 = 6.022 X 10^23
When 1.0 mole of O2 is completely consumed in the reaction to form NO, 1.0 mole of NO is produced since the balanced equation for the reaction is 2 O2 + 2 N2 -> 2 NO. This means that the mole ratio between O2 and NO is 1:1.
6.02214076×1023
Do you mean this reaction? 2Mg + O2 -> 2MgO 4.11 moles Mg (1 mole O2/2 mole Mg) = 2.06 moles oxygen gas consumed --------------------------------------------------
1.76 grams CO2 (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O2) = 4.82 X 10^22 atoms of oxygen gas
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
The balanced equation for the reaction must be given to determine the molar ratio between O2 and P2O5. Without that information, it is not possible to determine the exact number of moles of P2O5 produced from 8.00 moles of O2.
For the reaction 2 H2 + O2 -> 2 H2O, we see that 1 mole of O2 produces 2 moles of H2O. Therefore, to produce 10.2 moles of H2O, we would need 5.1 moles of O2.
Here is the BALANCED reaction eq'n. 2H2(g) + O2(g) = 2H2O(l) The prefix number are the Molar Ratios 2:1::2 So oxygen is ONE(1) mole Hence hydrogen is TWO(2) moles It produces TWO(2) moles of water.
Balanced equation first. 2H2 + O2 -> 2H2O 0.600 moles H2 (1 mole O2/2 moles H2)(6.022 X 10^23/1 mole O2) = 1.81 X 10^23 molecules of O2 required ------------------------------------------------------
2no12no plus o2?????Do you mean this decomposition equation?2NO --> N2 + O23.1 grams O2 (1 mole O2/32 grams)(2 moles NO/1 mole O2)(6.022 X 1023/1 mole NO)= 1.2 X 1023 atoms of nitric oxide needed============================( if this is not what you meant you can resubmit or contact me )
1 mole of 02 gas has 12,044 281 714.1023 atoms.
The balanced equation shows that 2 moles of H2S react with 3 moles of O2. Therefore, to react completely with 2.3 moles of H2S, you would need (3/2) x 2.3 moles of O2 which is equal to 3.45 moles of O2.