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To find the number of atoms in 1 gram of boron, we first need to know its molar mass, which is approximately 10.81 grams per mole. Using Avogadro's number, which is about (6.022 \times 10^{23}) atoms per mole, we can calculate the number of atoms in 1 gram of boron. The number of moles in 1 gram is (1 , \text{g} / 10.81 , \text{g/mol} \approx 0.0925 , \text{moles}). Thus, the number of atoms is approximately (0.0925 \times 6.022 \times 10^{23} \approx 5.57 \times 10^{22}) atoms.

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