Potassium hydroxide (KOH) consists of three types of atoms: one potassium (K) atom, one oxygen (O) atom, and one hydrogen (H) atom. In total, there are three atoms in a molecule of KOH.
The answer is 12,831 g KOH.
There are 3 atoms in each molecule of Potassium Hydroxide.The molecular formula is KOH. Hence, there is one atom of Potassium, one of Oxygen and one of Hydrogen.
35.28 (g) / 56.1056 (g/mol) = 0.6288 mol KOH
4.44 g KOH x 1 mole KOH/56 g = 0.0793 moles KOH(x L)(0.142 mole/L) = 0.0793 molesx = 0.558 L = 558 mls neededHCl + KOH ==> KCl + H2O
There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K. Therefore, 3.5 moles * 6.022E23 atoms/1 mole= 2.107E24
1 fomula unit of KOH has 3 atoms: 1 potassium (K), 1 oxygen (O), and 1 hydrogen (H).
1 gram of KOH is equivalent to approximately (1.55 \times 10^{22}) atoms. This can be calculated by converting the mass of KOH to moles using its molar mass, and then using Avogadro's number (6.022 x 10^23) to determine the number of atoms in 1 mole of KOH (1 mole = 1 formula unit = 1 formula weight in grams).
The answer is 12,831 g KOH.
The answer is10,436 g.
Atoms: 1 of potassium, 1 of manganese and 4 of oxygen.Total atoms: 6
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
There are 3 atoms in each molecule of Potassium Hydroxide.The molecular formula is KOH. Hence, there is one atom of Potassium, one of Oxygen and one of Hydrogen.
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35.28 (g) / 56.1056 (g/mol) = 0.6288 mol KOH
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To find the number of moles in 234.1 grams of KOH, first calculate the molar mass of KOH (39.1 g/mol for K, 16.0 g/mol for O, and 1.0 g/mol for H). Add up the molar masses to get 56.1 g/mol for KOH. Divide the given mass (234.1 g) by the molar mass (56.1 g/mol) to find that there are approximately 4.17 moles of KOH in 234.1 grams.
To calculate the number of moles of KOH, first find the molar mass of KOH which is 56.11 g/mol. Then, divide the given mass (1.350g) by the molar mass to get the number of moles. 1.350g / 56.11 g/mol = 0.024 moles of KOH.