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What is the molarity of a solution that contains 28g of KOH in 2 liters of solution?
To find the molarity (M) of the KOH solution, first calculate the number of moles of KOH. The molar mass of KOH is approximately 56.11 g/mol. Therefore, 28 g of KOH corresponds to about 0.498 moles (28 g ÷ 56.11 g/mol). Finally, the molarity is calculated as moles of solute per liter of solution: ( M = \frac{0.498 \text{ moles}}{2 \text{ L}} = 0.249 , M ). Thus, the molarity of the solution is approximately 0.25 M.
How many milliliters of 0.142 M HCl would be required to titrate 4.44 g KOH?
4.44 g KOH x 1 mole KOH/56 g = 0.0793 moles KOH(x L)(0.142 mole/L) = 0.0793 molesx = 0.558 L = 558 mls neededHCl + KOH ==> KCl + H2O
How do you make 0.1m KOH?
An 11 M KOH solution indicates there are 11 moles of KOH per liter of water. 1 mole of KOH has a volume of 27.4 mL, so to account for the added volume it is necessary to add 15.75 moles of KOH per liter of water, or 884 grams per liter.
How many grams of KOH are present in 31.5 mL of a 7.26M KOH solution?
The answer is 12,831 g KOH.
In the reaction mgcl2 plus 2koh mg(oh)2 plus 2kcl how many grams of koh react with 1 mile of mgcl?
In the reaction ( \text{MgCl}_2 + 2 \text{KOH} \rightarrow \text{Mg(OH)}_2 + 2 \text{KCl} ), it is clear that 1 mole of magnesium chloride ((\text{MgCl}_2)) reacts with 2 moles of potassium hydroxide ((\text{KOH})). Therefore, to determine the mass of (\text{KOH}) that reacts with 1 mole of (\text{MgCl}_2), you would need 2 moles of (\text{KOH}). Since the molar mass of (\text{KOH}) is approximately 56.11 g/mol, the total mass of (\text{KOH}) required is (2 \times 56.11 , \text{g} = 112.22 , \text{g}).
How many moles of KOH are represented by 1.350g of KOH?
To calculate the number of moles of KOH, first find the molar mass of KOH which is 56.11 g/mol. Then, divide the given mass (1.350g) by the molar mass to get the number of moles. 1.350g / 56.11 g/mol = 0.024 moles of KOH.
How many moles are in 234.1 grams of KOH?
To find the number of moles in 234.1 grams of KOH, first calculate the molar mass of KOH (39.1 g/mol for K, 16.0 g/mol for O, and 1.0 g/mol for H). Add up the molar masses to get 56.1 g/mol for KOH. Divide the given mass (234.1 g) by the molar mass (56.1 g/mol) to find that there are approximately 4.17 moles of KOH in 234.1 grams.
How many moles are present in 34 grams of KOH?
To determine the number of moles in 34 grams of KOH, we first need to calculate its molar mass. The molar mass of KOH is approximately 56.11 g/mol (potassium: 39.10 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol). Divide the given mass by the molar mass to find the number of moles: 34 g / 56.11 g/mol ≈ 0.61 moles of KOH.
In the reaction MgCl2 plus 2KOH---Mg(OH)2 plus 2KCl how many moles of KOH react with 1 mole of MgCl2?
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
How many grams of solid KOH is necessary to prepare 220.0 ml of 0.500 M KOH solution?
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
How many grams of koh are needed to prepare 250 milliliters of a 2 m solution of koh formula mass 56?
To prepare a 2 M solution of KOH, you would need to calculate the moles of KOH required first. Then use the formula mass of KOH (56 g/mol) to convert moles to grams. First, calculate the moles needed: 2 moles/L * 0.25 L = 0.5 moles. Then, convert moles to grams: 0.5 moles * 56 g/mole = 28 grams of KOH needed.
What mass of potassium hydroxide is required to react completely with 2.70 g of sulfuric acid to produce potassium sulfate and water?
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
In the reaction MgCl2 plus 2KOH to MgOH2 plus 2KCl how many moles of KOH react with 1 mole of MgCl2?
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
How many moles of KOH are contained in 750. mL of 5.00 M KOH solution?
To determine the number of moles of KOH in the solution, you can use the formula: moles = molarity x volume (L) First, convert the volume from mL to liters by dividing 750 mL by 1000. Then, multiply the molarity (5.00 M) by the volume in liters to find the number of moles of KOH in the solution.
What is the molarity of a solution that contains 28g of KOH in 2 liters of solution?
To find the molarity (M) of the KOH solution, first calculate the number of moles of KOH. The molar mass of KOH is approximately 56.11 g/mol. Therefore, 28 g of KOH corresponds to about 0.498 moles (28 g ÷ 56.11 g/mol). Finally, the molarity is calculated as moles of solute per liter of solution: ( M = \frac{0.498 \text{ moles}}{2 \text{ L}} = 0.249 , M ). Thus, the molarity of the solution is approximately 0.25 M.
How many milliliters of 0.142 M HCl would be required to titrate 4.44 g KOH?
4.44 g KOH x 1 mole KOH/56 g = 0.0793 moles KOH(x L)(0.142 mole/L) = 0.0793 molesx = 0.558 L = 558 mls neededHCl + KOH ==> KCl + H2O
Which equation shows how to calculate how many grams (g) of Mg(OH)2 would be produced from 4 mol of KOH The balanced reaction is MGCl2 plus 2KOH Mg(OH)2 plus 2KCl?
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
