8
Eight - it has a full outer shell of electrons.
Atoms do not actually have desires as such, although the metaphor can be useful. Atoms are more stable when they have a full outer electron shell. The smaller atoms, hydrogen, helium, lithium, and beryllium, can obtain a full outer shell with only two electrons in it. The heavier atoms require 8 electrons to have a full outer shell. That is known as the octet rule (an octet is a set of eight).
Oxygen needs 2 more valence electrons to have a full outer shell. Oxygen has 6 valence electrons, and a full outer shell for oxygen is achieved at 8 valence electrons.
Barium has 0 unpaired electrons. It has a full outer shell of electrons, which is why it is a stable element.
The symbol for an element that does not need eight electrons to have a full set of valence electrons is typically found in Group 1 or Group 2 of the periodic table. Examples include lithium (Li) from Group 1 and beryllium (Be) from Group 2. These elements follow the duet rule or satisfy the octet rule in a different way.
A full set of valence electrons typically consists of 8 electrons, except for hydrogen and helium, which have a full valence shell with 2 electrons.
no
It does.
Yes, it can.
An atom with 4 valence electrons will have to either gain 4 electrons or lose 4 electrons to achieve a full set of eight electrons.
Yes, it is true.
They will gain 3 electrons from something with 3 valence electrons.
An element that does not require eight electrons for a full set of valence electrons is represented by the element symbol B. Boron only needs six electrons to complete its valence shell and achieve stability.
The octet rule.
Phosphorus, with 5 valence electrons, needs to gain 3 electrons to have a full set of 8 valence electrons. This would allow it to achieve a stable octet configuration, resembling the noble gas configuration of argon.
Krypton has 8 valence electrons.
Eight - it has a full outer shell of electrons.