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How many grams of 137Ce must be produced now to have a sample containing 34 g of 137Ce 100 years from now?
To calculate the grams needed now, we use the radioactive decay formula: N(t) = N0 * (1/2)^(t/t1/2), where N(t) is the final amount, N0 is the initial amount, t is the time passed, and t1/2 is the half-life. Given the half-life of 137Ce is 30 years, we can calculate that approximately 136 grams of 137Ce need to be produced now to have 34 grams remaining after 100 years.
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How many grams of carbon dioxide are present in a sample containing 80.0 moles of CO2?
80,0 moles of CO2is equal to 3 520,8 g.
A sample of Se weighs 20.5 grams will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams?
A sample of Se weighs 20.5 grams. Will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams? (more, less): _______Calculate the mass of a sample of V that contains the same number of atoms. _______ grams of VAnswer:Since the atomic weight of V is smaller than the atomic weight of Se, each atom will have a smallermass, and the sample will weigh less.Since the same number of moles will contain the same number of atoms, regardless of the element, it is only necessary to find the number of moles of Se in the 20.5 gram sample, and then to find the mass of the same number of moles of V.The atomic weight of Se is 79.0 g/mol1. Convert grams of Se to moles of Se:moles Se= 20.5 g Se1 mol = 0.260 mol Se79.0 gMultiply by moles per gram. Grams cancel out.The atomic weight of V is 50.9 g/mol2. To convert 0.260 moles of V to grams of V:grams V = 0.260 mol V50.9 g = 13.2 g V1 molMultiply by grams per mole. Moles cancel out.
A sample of 0.53 grams of an ore contains 5.4 percent silver How many milligrams of pure silver are in the sample?
To calculate the amount of pure silver in the sample, multiply the mass of the ore by the percentage of silver: 0.53 grams * 5.4% = 0.02862 grams of silver. To convert grams to milligrams, multiply by 1000: 0.02862 grams * 1000 = 28.62 milligrams of pure silver in the sample.
A 10 ml sample of a substance has a mass of 20 grams what would be the mass of a 200 ml sample of the same substace?
The mass of the substance is 20 grams in a 10 ml sample. Therefore, the substance has a density of 2 grams/ml. For a 200 ml sample of the same substance, the mass would be 400 grams (200 ml x 2 grams/ml).
The mass of Denise's rock sample is 684 grams. The mass of Pauline's rock sample is 29,510 centigrams. How much greater is the mass of Denise's sample than Pauline's sample?
"centi" is 100. 1 centigram is 100 grams, so Denise's sample is 68,400 centigrams. 68400 - 29510 = 38890 centigrams or 388.90 grams.
How many grams of carbon dioxide are present in a sample containing 80.0 moles of CO2?
80,0 moles of CO2is equal to 3 520,8 g.
What is the method to calculate the mass in grams of each sample?
To calculate the mass in grams of each sample, you can use a balance or scale to measure the weight of the sample. The weight measured in grams is equivalent to the mass of the sample.
How many grams is 56.8 grams?
a metal sample weigs 56.8 gramsHow many ounces does this sample weigh?
A sample of Se weighs 20.5 grams will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams?
A sample of Se weighs 20.5 grams. Will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams? (more, less): _______Calculate the mass of a sample of V that contains the same number of atoms. _______ grams of VAnswer:Since the atomic weight of V is smaller than the atomic weight of Se, each atom will have a smallermass, and the sample will weigh less.Since the same number of moles will contain the same number of atoms, regardless of the element, it is only necessary to find the number of moles of Se in the 20.5 gram sample, and then to find the mass of the same number of moles of V.The atomic weight of Se is 79.0 g/mol1. Convert grams of Se to moles of Se:moles Se= 20.5 g Se1 mol = 0.260 mol Se79.0 gMultiply by moles per gram. Grams cancel out.The atomic weight of V is 50.9 g/mol2. To convert 0.260 moles of V to grams of V:grams V = 0.260 mol V50.9 g = 13.2 g V1 molMultiply by grams per mole. Moles cancel out.
A sample of 0.53 grams of an ore contains 5.4 percent silver How many milligrams of pure silver are in the sample?
To calculate the amount of pure silver in the sample, multiply the mass of the ore by the percentage of silver: 0.53 grams * 5.4% = 0.02862 grams of silver. To convert grams to milligrams, multiply by 1000: 0.02862 grams * 1000 = 28.62 milligrams of pure silver in the sample.
How many grams does a 0.0233 kg sample contain?
23.3 grams
How many grams is a sample containing 2.71 x 1024 atoms of iron?
Amount of Fe = (2.71x1024)/(6.02x1023) = 4.50mol The atomic mass of Fe is 55.8 Mass of Fe = 4.50 x 55.8 = 251g
A 10 ml sample of a substance has a mass of 20 grams what would be the mass of a 200 ml sample of the same substace?
The mass of the substance is 20 grams in a 10 ml sample. Therefore, the substance has a density of 2 grams/ml. For a 200 ml sample of the same substance, the mass would be 400 grams (200 ml x 2 grams/ml).
The mass of Denise's rock sample is 684 grams. The mass of Pauline's rock sample is 29,510 centigrams. How much greater is the mass of Denise's sample than Pauline's sample?
"centi" is 100. 1 centigram is 100 grams, so Denise's sample is 68,400 centigrams. 68400 - 29510 = 38890 centigrams or 388.90 grams.
Which is none concentrated solution containing 5 grams of salt and 10 grams of water or a solution containing 18 grams of salt and 90 grams of water?
The more concentrated solution is the one containing 18 grams of salt and 90 grams of water. This is because the concentration of the solute (salt) is higher in this solution compared to the solution containing 5 grams of salt and 10 grams of water.
A sample of Helium gas weighs 4.00 g (grams) and occupies 22.4 L (liters) when it is at 0 degree Celsius and 760 mm Hg pressure. What is the mass of the sample in grams?
The mass of the helium gas sample is already given as 4.00 grams. This value represents the weight of the gas under the specified conditions of temperature and pressure. Therefore, the mass of the sample is 4.00 grams.
What is concentrated containing 5 grams of salt in 10 grams of water 18 grams of salt in 90 grams soft water?
A solution containing 5 g sodium chloride in 10 g water doesn't exist.
