To calculate the amount of pure silver in the sample, multiply the mass of the ore by the percentage of silver: 0.53 grams * 5.4% = 0.02862 grams of silver. To convert grams to milligrams, multiply by 1000: 0.02862 grams * 1000 = 28.62 milligrams of pure silver in the sample.
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
The mass of the substance is 20 grams in a 10 ml sample. Therefore, the substance has a density of 2 grams/ml. For a 200 ml sample of the same substance, the mass would be 400 grams (200 ml x 2 grams/ml).
"centi" is 100. 1 centigram is 100 grams, so Denise's sample is 68,400 centigrams. 68400 - 29510 = 38890 centigrams or 388.90 grams.
The mass of the helium gas sample is already given as 4.00 grams. This value represents the weight of the gas under the specified conditions of temperature and pressure. Therefore, the mass of the sample is 4.00 grams.
a metal sample weigs 56.8 gramsHow many ounces does this sample weigh?
23.3 grams
Balanced equation. 2K + Cl2 >> 2KCl 39 grams K (1mol K/39.10g )(1mol Cl/2mol K )(35.45g/1 mol Cl ) = 17.7 grams
There are 57.6 grams of tin in that sample.
To calculate the amount of pure silver in the sample, multiply the mass of the ore by the percentage of silver: 0.53 grams * 5.4% = 0.02862 grams of silver. To convert grams to milligrams, multiply by 1000: 0.02862 grams * 1000 = 28.62 milligrams of pure silver in the sample.
To find the mass of 64 moles of Cl (chlorine), you need to multiply the number of moles by the molar mass of Cl. The molar mass of Cl is approximately 35.45 g/mol. Therefore, 64 moles of Cl would be approximately 2267.2 grams (64 moles x 35.45 g/mol).
To calculate the mass in grams of each sample, you can use a balance or scale to measure the weight of the sample. The weight measured in grams is equivalent to the mass of the sample.
To determine how many grams of chlorine gas (Cl₂) are produced from the decomposition of sodium chloride (NaCl), we start with the balanced chemical equation for the reaction: 2 NaCl → 2 Na + Cl₂. From the molar mass of NaCl (approximately 58.44 g/mol), 7.5 grams of NaCl corresponds to about 0.128 moles. According to the stoichiometry of the reaction, 2 moles of NaCl produce 1 mole of Cl₂, so 0.128 moles of NaCl would yield 0.064 moles of Cl₂. The molar mass of Cl₂ is approximately 70.90 g/mol, resulting in about 4.54 grams of Cl₂ being produced.
Since 1 centiliter (cl) is equal to 1 gram for water and other similar liquids, 8 centiliters would be equal to 8 grams.
15cL equals 0.15L* There are 100cL per liter
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
There are 1.5 moles of water molecules in a 27 gram sample of water. This is calculated by dividing the mass of the sample (27 grams) by the molar mass of water (18 grams/mol).