16g
999 g
42,09 g silver chloride are obtained.
I'm happy to help, but I need the specific reactions in question in order to provide a detailed calculation. Once you provide the reactions, I can assist you in determining the grams of the first reactant needed to react with 56.5 g of the second reactant.
266,86 g aluminium chloride are obtained.
800 g oxygen are needed.
160...cant quite grasp HOW though
For every 1 gram of zinc, 3.88 grams of iodine are required to react. So in this case, with 4.2 grams of zinc, the amount of iodine needed would be (4.2 grams zinc) * (3.88 grams iodine / 1 gram zinc) = 16.296 grams of iodine.
999 g
Since oleic acid has one double bond, it can react with 1 mol of hydrogen (2 g) per double bond in a process called hydrogenation. Therefore, 75g of oleic acid requires 2g of hydrogen to saturate the double bond.
2
The balanced chemical equation for the reaction is: 4Fe + 3O2 -> 2Fe2O3 From the equation, it can be seen that 3 moles of O2 are required to react with 4 moles of Fe. Therefore, to determine the grams of O2 required to react with 100 g Fe, you would need to use stoichiometry to find the answer.
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
Two atoms of sodium are required to react with one molecule of Br2 to form sodium bromide. Therefore, to completely react with 5 molecules of Br2, you would need 10 atoms of sodium.
NaCl doesn't neutralize sulfuric acid.
In the reaction 3H2 + N2 --> 2NH3, the ratio of H2 to N2 is 3:1. To calculate the amount of N2 required, we need to first convert the mass of H2 to moles, then use the ratio to find the moles of N2 needed, and finally convert the moles of N2 to grams. After the calculation, we find that 2.79 g of H2 requires 3.31 g of N2 to react completely.
1 mole of H2 reacts with 1 mole of Cl2 to produce 2 moles of HCl. The molar mass of Cl2 is 70.9 g/mol. Since 0.65 g of H2 is used, we must calculate the molar amount of chlorine needed, which is 70.9 g/mol x 0.65 g / 2 g. This gives us approximately 23 grams of chlorine required.
100, of course.