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How many grams of oxygen will be required to reacts completely with 0.3 moles of aluminium?
999 g
If a solution containing 110.97 g of silver nitrate is allowed to react completely with a solution containing 12.45 g of lithium chloride how many grams of solid precipitate will be formed?
42,09 g silver chloride are obtained.
For each of the following precipitation reactions calculate how many grams of the first reactant are necessary to completely react with 56.5 g of the second reactant?
I'm happy to help, but I need the specific reactions in question in order to provide a detailed calculation. Once you provide the reactions, I can assist you in determining the grams of the first reactant needed to react with 56.5 g of the second reactant.
How many grams of aluminum chloride are produced when 54 grams of aluminum react with chlorine gas?
266,86 g aluminium chloride are obtained.
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many grams of fe2o3 are required to completely react with 84 grams of co?
160...cant quite grasp HOW though
Given that zinc reacts with iodine in the fixed mass ratio of 1 gram of zinc to 3.88 grams of iodine how many grams of iodine are required to completely react with 4.2 grams of zinc?
For every 1 gram of zinc, 3.88 grams of iodine are required to react. So in this case, with 4.2 grams of zinc, the amount of iodine needed would be (4.2 grams zinc) * (3.88 grams iodine / 1 gram zinc) = 16.296 grams of iodine.
How many grams of oxygen will be required to reacts completely with 0.3 moles of aluminium?
999 g
How many grams of hydrogen are required to completely saturate 75g oleic acid which has one double bond?
Since oleic acid has one double bond, it can react with 1 mol of hydrogen (2 g) per double bond in a process called hydrogenation. Therefore, 75g of oleic acid requires 2g of hydrogen to saturate the double bond.
How many grams of bromine will be required to react with 35.23 g of potassium for complete conversion to potassium bromide?
2
How many grams of Oxygen are required to react with 100 g Fe in this reaction?
The balanced chemical equation for the reaction is: 4Fe + 3O2 -> 2Fe2O3 From the equation, it can be seen that 3 moles of O2 are required to react with 4 moles of Fe. Therefore, to determine the grams of O2 required to react with 100 g Fe, you would need to use stoichiometry to find the answer.
How many grams of oxygen are required to burn 100 gram of propane?
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
How many atoms of sodium are required to completely react with 5 molecules of Br2 to form the ionic compound sodium bromide?
Two atoms of sodium are required to react with one molecule of Br2 to form sodium bromide. Therefore, to completely react with 5 molecules of Br2, you would need 10 atoms of sodium.
How many grams of Nacl are required to completely neutralized of 100ml of 1Molerityof H2SO4?
NaCl doesn't neutralize sulfuric acid.
How many grams of nitrogen are required to react with 2.79 g of hydrogen to produce ammonia?
In the reaction 3H2 + N2 --> 2NH3, the ratio of H2 to N2 is 3:1. To calculate the amount of N2 required, we need to first convert the mass of H2 to moles, then use the ratio to find the moles of N2 needed, and finally convert the moles of N2 to grams. After the calculation, we find that 2.79 g of H2 requires 3.31 g of N2 to react completely.
How many grams of chlorine are required to completely react with 0.65 g of H2 to produce HCl?
1 mole of H2 reacts with 1 mole of Cl2 to produce 2 moles of HCl. The molar mass of Cl2 is 70.9 g/mol. Since 0.65 g of H2 is used, we must calculate the molar amount of chlorine needed, which is 70.9 g/mol x 0.65 g / 2 g. This gives us approximately 23 grams of chlorine required.
How many grams of O2 must react to get 100 grams of O3?
100, of course.
