420 kcal
The number of moles is 2,997.
0,83moles glucose are burned.
To calculate the kilocalories released by freezing 3.1 moles of H2O, we need to use the heat of fusion for water, which is approximately 6.01 kJ/mol. First, convert this to kilocalories: 6.01 kJ/mol is about 1.43 kcal/mol. For 3.1 moles, the total energy released would be 3.1 mol × 1.43 kcal/mol = 4.43 kcal. Therefore, freezing 3.1 moles of H2O releases approximately 4.43 kilocalories.
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
The solution is 0,25 M.
2.,7 moles of glucose have 486,432 g.
The number of moles is 2,997.
0,83moles glucose are burned.
To calculate the kilocalories released by freezing 3.1 moles of H2O, we need to use the heat of fusion for water, which is approximately 6.01 kJ/mol. First, convert this to kilocalories: 6.01 kJ/mol is about 1.43 kcal/mol. For 3.1 moles, the total energy released would be 3.1 mol × 1.43 kcal/mol = 4.43 kcal. Therefore, freezing 3.1 moles of H2O releases approximately 4.43 kilocalories.
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
38
To form ethanol, the chemical equation shows that one mole of glucose is converted to two moles of ethanol. The molar mass of glucose is around 180 g/mol and that of ethanol is around 46 g/mol. Therefore, to produce 127g of ethanol, you would need 127g/(46g/mol) = 2.76 moles of ethanol. Since glucose to ethanol is a 1:2 ratio, you would need half as many moles of glucose, which would be 1.38 moles of glucose.
The solution is 0,25 M.
0.67 moles of C6H12O6
One mole of glucose requires six moles of CO2 to enter the Calvin cycle for its synthesis.
The answer is of course 6 moles.
To find the number of moles of glucose (C₆H₁₂O₆) in 540 grams, first calculate the molar mass of glucose: (6 × 12.01) + (12 × 1.008) + (6 × 16.00) = 180.18 g/mol. Then, use the formula: moles = mass (g) / molar mass (g/mol). Thus, the number of moles in 540 grams of glucose is 540 g / 180.18 g/mol ≈ 3.00 moles.