2.,7 moles of glucose have 486,432 g.
There are 1.5 moles of water molecules in a 27 gram sample of water. This is calculated by dividing the mass of the sample (27 grams) by the molar mass of water (18 grams/mol).
There are approximately 27 grams in 1.5 moles of water.
To find the number of moles of fluorine in 27 grams of oxygen difluoride (OF2), first calculate the molar mass of OF2, which is 71 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 27 grams divided by 71 g/mol equals approximately 0.38 moles of OF2. Since there are two moles of fluorine in one mole of OF2, multiply the moles of OF2 by 2 to find that there are approximately 0.76 moles of fluorine in 27 grams of OF2.
For this you need the atomic mass of Al. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.54.0 grams Al / (27.0 grams) = 2.00 moles Al
About 907.2 grams.
One mole weights 26.98 grams, so it is arouind 27 g. So 4 moles weight almost 108 grams.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
To determine how many grams of zinc chloride (ZnCl₂) are needed to react with 45 grams of aluminum (Al), we first need to look at the balanced chemical equation for the reaction, which is: [ 2Al + 3ZnCl₂ \rightarrow 2AlCl₃ + 3Zn ] From the equation, 2 moles of aluminum react with 3 moles of zinc chloride. The molar mass of aluminum is approximately 27 g/mol, so 45 grams of aluminum corresponds to about 1.67 moles of Al. Thus, we need 2.5 moles of ZnCl₂ (since 1.67 moles Al will require 2.5 moles ZnCl₂). The molar mass of ZnCl₂ is about 136.3 g/mol, so 2.5 moles of ZnCl₂ would weigh approximately 340.75 grams.
To find the number of moles of atoms in 9 grams of aluminum, you can use the molar mass of aluminum, which is approximately 27 g/mol. Dividing the mass of aluminum (9 g) by its molar mass (27 g/mol) gives you about 0.33 moles of aluminum. Since each aluminum atom is a single atom, there are also 0.33 moles of atoms in 9 grams of aluminum.
The formular you need is M = n/m (molar mass = amount of substance/mass), or n = m/MAluminium has a molar mass of 26.982 g/mol. The given mass is 3 grams. Therefore:n(Al) = 3g / (26.982g/mol) = 0.11mol
First, calculate the molar mass of N2H4 (hydrazine) to be 32 g/mol. Use the stoichiometry of the balanced equation to find the molar ratio of N2H4 to H2O, which is 1:4. Next, determine the number of moles of N2H4 in 27 grams and then use the molar ratio to find the number of moles of H2O produced. Finally, convert the moles of H2O to grams using the molar mass of H2O (18 g/mol).
For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaCl=58 grams 25.0 grams NaCl / (58 grams) = .431* moles NaCl *approximation