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How many moles in 5.67 grams of fluorine gas?
To find the number of moles in 5.67 grams of fluorine gas, you need to divide the mass by the molar mass of fluorine. The molar mass of fluorine is approximately 19 g/mol. Therefore, 5.67 grams of fluorine gas is equal to 5.67 g / 19 g/mol ≈ 0.298 mol.
How many moles of fluorine are present in 2.67 grams of nitrogen trifluoride moles?
To determine the number of moles of fluorine present in 2.67 grams of nitrogen trifluoride (NF3), we first need to calculate the molar mass of NF3, which is 71.0 g/mol. Then we find the moles of NF3 in 2.67 g by dividing the mass by the molar mass: 2.67 g / 71.0 g/mol ≈ 0.038 moles. As there are three fluorine atoms in each molecule of NF3, there are 3 times more moles of fluorine: 0.038 moles NF3 x 3 = 0.114 moles of fluorine.
What is the mass of 3moles of oxygen?
The molar mass of oxygen is approximately 16 grams/mol. Therefore, the mass of 3 moles of oxygen would be 3 moles * 16 grams/mole = 48 grams.
How many moles are in 64 grams of oxygen gas?
four moles. Approximately. Oxygen has a molecular weight of 16.0 grams per mole so 64 grams divided by 16.0 grams per mole is four moles.
How many grams of Oxygen is in 6 O2?
There are 192 grams of oxygen in 6 moles of O2.
How many moles are there in 1.8 grams of fluorine?
1,8 grams of fluorine is equivalent to 0,0947 moles.
How many moles in 76 grams of fluorine?
To find the number of moles in 76 grams of fluorine, you first need to determine the molar mass of fluorine, which is approximately 19 grams per mole. Then, you divide the given mass (76 grams) by the molar mass of fluorine to get the number of moles. In this case, 76 grams of fluorine is equal to approximately 4 moles.
What is 16 grams of oxygen how many moles?
16 grams of oxygen how many moles is 0,5 moles.
If you have 85.5 grams of fluorine which has a molar mass approxidmatley 19 g mol how many moles of fluorine do you have?
To calculate the number of moles of fluorine, divide the given mass (85.5 grams) by the molar mass of fluorine (19 g/mol). Number of moles of fluorine = 85.5 g / 19 g/mol ≈ 4.5 moles.
What is the empirical formula of a compound consisting of 29.6 percent oxygen and 70.4 percent fluorine by mass?
We assume 100 grams total and turn those percentages into grams. Get moles elements. 29.6 grams O (1 mole O/16.0 grams) = 1.85 mole O 70.4 grams F (1 mole F/19.0 grams) = 3.71 mole F now divide both moles by smallest number to get mole ratio for empirical formula 1.85/1.85 = 1 for O 3.71/1.85 = 2 for F so the empirical formula for this compound is........ OF2
How many moles in 5.67 grams of fluorine gas?
To find the number of moles in 5.67 grams of fluorine gas, you need to divide the mass by the molar mass of fluorine. The molar mass of fluorine is approximately 19 g/mol. Therefore, 5.67 grams of fluorine gas is equal to 5.67 g / 19 g/mol ≈ 0.298 mol.
How many moles of in 320 grams of oxygen?
320 grams of oxygen is the equivalent of 10 moles.
How many moles are there in 12.8grammes of oxygen?
12.8 grams oxygen (1 mole O/16.0 grams) = 0.800 moles of oxygen
How many grams of oxygen will be in 2 moles of pottassium dichromate?
The answer is 224,141 grams oxygen.
How many moles are in 0.667 grams of oxygen?
0,667 g oxygen equal 0,021 moles.
How many moles of fluorine are present in 2.67 grams of nitrogen trifluoride moles?
To determine the number of moles of fluorine present in 2.67 grams of nitrogen trifluoride (NF3), we first need to calculate the molar mass of NF3, which is 71.0 g/mol. Then we find the moles of NF3 in 2.67 g by dividing the mass by the molar mass: 2.67 g / 71.0 g/mol ≈ 0.038 moles. As there are three fluorine atoms in each molecule of NF3, there are 3 times more moles of fluorine: 0.038 moles NF3 x 3 = 0.114 moles of fluorine.
What is the mass of 3moles of oxygen?
The molar mass of oxygen is approximately 16 grams/mol. Therefore, the mass of 3 moles of oxygen would be 3 moles * 16 grams/mole = 48 grams.
