To determine how much calcium-47 remains after 27 days, we need to know its half-life, which is about 4.5 days. After 27 days, which is approximately 6 half-lives, the amount remaining can be calculated using the formula: ( \text{remaining} = \text{initial} \times \left( \frac{1}{2} \right)^{\text{number of half-lives}} ). Therefore, starting with 63 mg, the calculation would be ( 63 \times \left( \frac{1}{2} \right)^6 ), resulting in approximately 0.98 mg remaining.
After 4 days, only 1/16 of the original amount of gold (198/16 = 12.375) will remain.
After 24,10(3) days (the half-time of this isotope) the mass is 50 %.
1250 on day six
The mass is 1,075 g.
After 10 days, 1/2 of the original isotope will remain since its half-life is 5 days. This means 6kg of the original isotope will remain after 1 half-life, which remains the same after 10 days since another half-life has passed.
reference table N: Half Life of Rn-222 is 3.823d = 8/3.823 = # of Half lives = 2.09 (roughly 2) 20g-> 40g-> 80g doesn't say anything about decay so assume to increase since how much will remain in 8days Ans: 80g
120. 10 milligrams twice a day would be 20 milligrams a day. 20 milligrams a day/ 5 milligrams in a tablet = 4 tablets a day. multiply that by 30 days and you get the answer.
To determine how much calcium-47 remains after 27 days, we need to know its half-life, which is about 4.5 days. After 27 days, which is approximately 6 half-lives, the amount remaining can be calculated using the formula: ( \text{remaining} = \text{initial} \times \left( \frac{1}{2} \right)^{\text{number of half-lives}} ). Therefore, starting with 63 mg, the calculation would be ( 63 \times \left( \frac{1}{2} \right)^6 ), resulting in approximately 0.98 mg remaining.
Milligrams in a carat.
7-14 days
initial test will be held on diffirent days respectively.
.05 grams = .05(1000) = 50 milligrams 3(50 milligrams) = 150 milligrams 150 milligrams/25 milligrams = 6 So you should order six 25 milligram capsules This answer is only sufficient for 1 day. The physician wants 50 mg three times a day for 2 days which is 300 mg = 12 capsules. Patent takes 2 capsules at each dosage time. Brian Jones
After 28 days, two half-lives would have passed (14 days x 2). This means the initial amount of phosphorus-32 would be reduced by three-quarters (1/2 x 1/2 = 1/4). Therefore, 6 mg (24 mg x 1/4) of phosphorus-32 will remain after 28 days.
After 4 days, only 1/16 of the original amount of gold (198/16 = 12.375) will remain.
i need to mknow because my father was charged with murder of my mom and he didnt do it and there was 8 milligrams of strychnine in her blood.
30 days