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To determine how much calcium-47 remains after 27 days, we need to consider its half-life, which is approximately 4.54 days. After 27 days, which is about six half-lives (27 days / 4.54 days ≈ 5.95), the remaining amount can be calculated using the formula ( \text{Remaining amount} = \text{Initial amount} \times \left( \frac{1}{2} \right)^{\text{number of half-lives}} ). Therefore, ( 63 , \text{mg} \times \left( \frac{1}{2} \right)^6 \approx 63 , \text{mg} \times 0.015625 \approx 0.984375 , \text{mg} ). Thus, approximately 0.98 mg of calcium-47 remains after 27 days.
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How many milligrams of an initial 63 of calcium-47 remain after 27?
To determine how much calcium-47 remains after 27 days, we need to know its half-life, which is about 4.5 days. After 27 days, which is approximately 6 half-lives, the amount remaining can be calculated using the formula: ( \text{remaining} = \text{initial} \times \left( \frac{1}{2} \right)^{\text{number of half-lives}} ). Therefore, starting with 63 mg, the calculation would be ( 63 \times \left( \frac{1}{2} \right)^6 ), resulting in approximately 0.98 mg remaining.
After how many days 1-4 of the original amount of gold 198 will remain?
After 4 days, only 1/16 of the original amount of gold (198/16 = 12.375) will remain.
How much mass remains in Thorium 234 after a half?
After 24,10(3) days (the half-time of this isotope) the mass is 50 %.
You start out with 10000 radioactive atoms Their half life is 2 days How many will remain in 6 days?
1250 on day six
How much of a g sample of barium-131 would remain after 36 days?
The mass is 1,075 g.
A radioactive substance has has life of 5 days initial mass of 12kg how much the original isotope will remain after 10 days?
After 10 days, 1/2 of the original isotope will remain since its half-life is 5 days. This means 6kg of the original isotope will remain after 1 half-life, which remains the same after 10 days since another half-life has passed.
How much of a 20-g sample of radon-222 will remain after eight days?
reference table N: Half Life of Rn-222 is 3.823d = 8/3.823 = # of Half lives = 2.09 (roughly 2) 20g-> 40g-> 80g doesn't say anything about decay so assume to increase since how much will remain in 8days Ans: 80g
How many 5 milligram tablets should you dispense for 30 days if the prescription is 10 milligrams twice daily for 30 days?
120. 10 milligrams twice a day would be 20 milligrams a day. 20 milligrams a day/ 5 milligrams in a tablet = 4 tablets a day. multiply that by 30 days and you get the answer.
How many milligrams of an initial 63 of calcium-47 remain after 27?
To determine how much calcium-47 remains after 27 days, we need to know its half-life, which is about 4.5 days. After 27 days, which is approximately 6 half-lives, the amount remaining can be calculated using the formula: ( \text{remaining} = \text{initial} \times \left( \frac{1}{2} \right)^{\text{number of half-lives}} ). Therefore, starting with 63 mg, the calculation would be ( 63 \times \left( \frac{1}{2} \right)^6 ), resulting in approximately 0.98 mg remaining.
If 7diaw is 7 days in a week what is 200miac?
Milligrams in a carat.
If I took 90 milligrams one day and then the next day I took 15 milligrams of methadone how long will it stay in my system?
7-14 days
What is date of initial test of pak army?
initial test will be held on diffirent days respectively.
How many capsules should you order for two days if the physician prescribes a medication 0.05 grams 3 times a day for two days and the pharmacy carries this medication in 25 milligram capsules?
.05 grams = .05(1000) = 50 milligrams 3(50 milligrams) = 150 milligrams 150 milligrams/25 milligrams = 6 So you should order six 25 milligram capsules This answer is only sufficient for 1 day. The physician wants 50 mg three times a day for 2 days which is 300 mg = 12 capsules. Patent takes 2 capsules at each dosage time. Brian Jones
During an experiment a solution containing 24 mg of phosphorus 32 was preparedHow much of the isotope will remain after 28 days if its half-life is 14 days?
After 28 days, two half-lives would have passed (14 days x 2). This means the initial amount of phosphorus-32 would be reduced by three-quarters (1/2 x 1/2 = 1/4). Therefore, 6 mg (24 mg x 1/4) of phosphorus-32 will remain after 28 days.
Does 8 milligrams of strychnine in your blood take days to do or can it get that high from one single dose?
i need to mknow because my father was charged with murder of my mom and he didnt do it and there was 8 milligrams of strychnine in her blood.
The half life of Au198 is 2 7 days When there are 800 atoms of Au198 in a sample a scientist starts a stopwatch The scientist stops the stopwatch at 8 1 days there are atoms of Au198 rema?
At 8.1 days, 400 atoms of Au198 would remain in the sample. This is because after 8.1 days, two half-lives of Au198 have passed, reducing the initial 800 atoms to 400.
After how many days 1-4 of the original amount of gold 198 will remain?
After 4 days, only 1/16 of the original amount of gold (198/16 = 12.375) will remain.
