reference table N: Half Life of Rn-222 is 3.823d
=
8/3.823 = # of Half lives = 2.09 (roughly 2)
20g-> 40g-> 80g
doesn't say anything about decay so assume to increase since how much will remain in 8days
Ans: 80g
Approx 196 milligrams.
25 g
1
If the half-life of a nuclide is 44.5 days, then 178 days is four half-lives. After four half-lives, 0.0625 (0.54) of the original nuclide remains. If 50g is the original mass, then the mass after 4 half-lives is 3.125g. AT = A0 2(-T/H) A178 = (50) 2(-44.5/178) A178 = 3.125
a radio active substance has half life of 5 days initial mass of 12kg.how much the original isotope will remain after 10 days?
If a sample of radioactive material has a half-life of one week the original sample will have 50 percent of the original left at the end of the second week. The third week would be 25 percent of the sample. The fourth week would be 12.5 percent of the original sample.
If a radioactive sample contains 1.25g of an isotope with a half-life of 4.0 days, then 0.625g (1/2) of the isotope will remain after 4.0 days, 0.3125g (1/4) after 8.0 days, 0.15625g (1/8) after 12.0 days, etc. AT = A0 2(-T/H)
Iodine-131 has a half-life of about 8 days.
The answer depends on 3240 WHAT: seconds, days, years?
The mass is 1,075 g.
The mass is 1,075 g.
12.5 g
it all really depends on your body. for me it took eight days. I had to do court ordered drug tests
Your sample of phosphorous will literally half itself every 14 days. So after 14 days there is 12mg left. After 28 days, there is 6mg remaining.
79 grams <><><><><> AT = A0 2 (-T/H) AT = 250 2(-40/24.1) AT = ~79
There are 192 hours in eight days.
If the half-life of a nuclide is 44.5 days, then 178 days is four half-lives. After four half-lives, 0.0625 (0.54) of the original nuclide remains. If 50g is the original mass, then the mass after 4 half-lives is 3.125g. AT = A0 2(-T/H) A178 = (50) 2(-44.5/178) A178 = 3.125
There are 9 5/7 days in sixty-eight days.
Eight Days Away was created in 2002.
Dilber's Eight Days was created in 2008.