32.9 g / 32.0 (g/molO2) = 1.028 mol O21.028 (O2) * 2 (H2O) * 18.02 (g/mol ) = 37.1 gram H2O
55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.
To find the mass of 1.54 moles of H2O, you can use the molar mass of water. The molar mass of H2O is 18.015 grams/mol. Therefore, the mass of 1.54 moles of H2O would be 1.54 moles * 18.015 grams/mol = approximately 27.75 grams.
The answer is 8,64 g.
C5H12 + 8 O2 --> 5 CO2 + 6 H2O (1 mol O2)(6 mol H2O/8 mol O2) = 0.75 mol H2O
In 1 molecule of H2O, there are 2 atoms of H. Therefore, in 1 mol of H2O, there are 2 mol of H. So, in 4.51 mol of H2O, there would be 4.51 * 2 = 9.02 mol of H.
There are 3.505 x 10^23 molecules of H2O in 0.583 mol of H2O, because 1 mol of any substance contains 6.022 x 10^23 molecules.
The chemical reaction isȘTiCl4 + 2 H2O = TiO2 + 2 HCl13 moles water are needed.
Neither H2O nor MgSO4 are elements. They are COMPOUNDS. In terms of volume occupied , MgSO4 is the larger.
32.9 g / 32.0 (g/molO2) = 1.028 mol O21.028 (O2) * 2 (H2O) * 18.02 (g/mol ) = 37.1 gram H2O
H2O's molar mass is 18 g/mol.
55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
To calculate the number of moles in 8g of H2O, we must first calculate the molar mass of H2O (18.015 g/mol). Then, we can use the formula moles = mass / molar mass to find that there are approximately 0.444 moles of H2O in 8g.
To find the grams of H2O and C3H6 formed from 6g of C3H8O, first calculate the molar mass of C3H8O: 44.1 g/mol. Then, using the stoichiometry of the reaction yielding H2O and C3H6 from C3H8O, you can determine the grams produced. The balanced reaction is C3H8O -> H2O + C3H6, and for every 1 mol of C3H8O, you get 1 mol of H2O and 1 mol of C3H6. So, 6g of C3H8O yields 6g of H2O and 6g of C3H6.
If burnt with excess O2 then 19.65 (=3*6.55) mole H2O
C2H4 + H2O --> C2H5OHReaction balanced at 1:1:1 mole of each compound, so you'll need 0.132 mol C2H4 and this is equal to:0.132 (mol C2H4) * 28 (g/mol C2H4) = 3.696 g C2H4 = 3.70 g C2H4