The answer is 12,046.1023 molecules.
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
There are approximately 2.41 x 10^23 molecules in 0.400 mol of N2O5. This is calculated by multiplying Avogadro's number (6.022 x 10^23 mol^-1) by the number of moles given.
3.54 (mol) * 6.02*1023 (molecules/mol) = 2.13*1024molecules (of any substance)
To calculate the number of water molecules in 1.802 grams, first find the molar mass of water (H2O = 18.015 g/mol). Then, divide the given mass by the molar mass to get the number of moles (1.802 g / 18.015 g/mol = 0.1 mol). Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of water molecules (0.1 mol * 6.022 x 10^23 molecules/mol = 6.022 x 10^22 molecules).
There are (5.41 \times 10^{23}) molecules of (O_2) in 0.900 moles.
The answer is 12,046.1023 molecules.
There are 6.022x10^23 molecules in 1.00 mol of anything.
There are 3.80 x 10^24 molecules of CO2 in 6.30 mol. This can be calculated by using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
There are approximately 5.8 x 10^24 molecules in 9.6 mol of C2H4. This is calculated using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
The number of molecules is 7,2265690284.10e23.
5.95378*1023
There are 3.505 x 10^23 molecules of H2O in 0.583 mol of H2O, because 1 mol of any substance contains 6.022 x 10^23 molecules.
There are approximately 2.41 x 10^23 molecules in 0.400 mol of N2O5. This is calculated by multiplying Avogadro's number (6.022 x 10^23 mol^-1) by the number of moles given.
2.65 mol * 64.07 g/mol = 169.79 g
1 mole H2O = 6.022 x 1023 molecules 0.357mol H2O x 6.022 x 1023 molecules/mol = 2.15 x 1023 molecules H2O