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How many milliliters of 0.305M NaOH would be required to titrate a 5.00mL solution of 0.616M HBr?
Since NaOH and HBr react in a 1:1 ratio, the moles of NaOH needed to titrate HBr can be calculated. Moles of NaOH = moles of HBr. Next, use the concentration and volume of HBr to find the moles present. Finally, use the concentration of NaOH to calculate the volume needed. In this case, approximately 2.41 mL of 0.305M NaOH would be needed.
How many grams HBr are required to produce 150g AlBr3 in the equation 2Al plus 6HBr producing 2AlBr3 and 3H2?
Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
What is the chemical formula for Dextromethorphan HBr?
The chemical formula for Dextromethorphan Hydrobromide (HBr) is C18H25NO·HBr.
How many grams in 4.23 m mol of HBr?
The answer is 0,3422 grams.
Is Hbr non polar or Polar?
Polar!
How many moles are present in 1.21 molecules of HBr?
To find the number of moles in 1.21 molecules of HBr, divide the number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol). Thus, 1.21 molecules of HBr is approximately 2.01 x 10^-24 moles.
How many moles are in 186 grams of HBr?
For this you need the atomic (molecular) mass of HBr. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. HBr= 81.0 grams186 grams HBr / (81.0 grams) =2.30 moles HBr
How many grams of solid sodium hydroxide would need to be added to completely neutralize 35.0 mL of 1.45 M HBr?
This is a titration question: we want to have the same number of hydroxide ions as hydroxide ions so that they will form water and the pH will be neutral. In chemistry, we count atoms and molecules in moles, and we can calculate how many moles of HBr we have, because concentration in molarity is the number of moles divided by the volume in liters... M = moles/V. We plug in what we got: 1.45M = moles/0.0350L, and solve for moles: 0.0508 moles. Now we know we need 0.0508 moles of NaOH, whose molecular weight is 40g/mole. MW x moles = grams, so (40g/mole)(0.0508 moles) = 2.03 g of NaOH.
How many kilojoules are associated with the formation of 2 moles of HBr?
The standard enthalpy of formation of HBr is -36.3 kJ/mol. For 2 moles of HBr, the total energy associated with the formation would be: -36.3 kJ/mol * 2 mol = -72.6 kJ.
How many moles are in 135 g of hydrobromic acid?
To calculate moles use the eq'n moles = mass(g) / Mr (Relative molceular Mass). We have a mass of 135 g The Mr is calcualted from the Periodic Table, using atomic weights/masses. HBr = 1 x H = 1 x 1 = 1 1 x Br = 1 x 79.9 = 79.9 79.9 + 1 = 80.9 Substituting into the eq'n moles(HBr) = 135 / 80.9 Moles = 1.66872..... ~ 1.67 moles.
What is the concentration of a HBr solution in 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
Balanced equation. KOH + HBr -> KBr + H2O everything is one to one, so... Molarity = moles of solute/liters of solution ( change ml to liters ) 0.25 M KOH = moles KOH/0.015 liters = 0.00375 moles of KOH this is as many moles that you have of HBr, so... Molarity of HBr = 0.00375 moles/0.012 liters = a concentration of HBr that is 0.31 M
How many milliliters of 0.305M NaOH would be required to titrate a 5.00mL solution of 0.616M HBr?
Since NaOH and HBr react in a 1:1 ratio, the moles of NaOH needed to titrate HBr can be calculated. Moles of NaOH = moles of HBr. Next, use the concentration and volume of HBr to find the moles present. Finally, use the concentration of NaOH to calculate the volume needed. In this case, approximately 2.41 mL of 0.305M NaOH would be needed.
What is the concentration of a HBr if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
To find the concentration of HBr, you first need to determine the number of moles of KOH that react with the HBr. This can be done using the volume and concentration of KOH solution. Then, using the stoichiometry of the neutralization reaction between HBr and KOH, you can find the number of moles of HBr present in the sample. Finally, divide the moles of HBr by the volume of the sample (12.0 mL) to obtain the concentration of HBr.
How many kilo-joules are associated with the formation of 2 moles of HBr(g)?
The standard enthalpy of formation of HBr(g) is -36.2 kJ/mol. For 2 moles of HBr(g), the total energy associated with its formation would be 2 * -36.2 kJ/mol = -72.4 kJ.
How many grams are in 5.00x10^24 molecules of lithium hydroxide?
A mole is the quantity of any molecule, atom, etc that has the same number of ... If I have 6.022×1023 H2 molecules, I have a mass of 2 gram of hydrogen molecules. ... How many moles are present in 1.21 X 10^24 molecules of HBr? ... How do you convert the amount of atoms in each battery to moles of lithium atoms?
A 25.00 mL sample of HBr is titrated with 0.150 M standardized sodium hydoxide solution the endpoint was reached when 18.80 mL of titrant had been added calculate the molar concentration of the HBr?
Using the balanced chemical equation for the reaction between HBr and NaOH (1:1 ratio), we can determine the moles of NaOH used. From the volume of NaOH used, we can then calculate the moles of HBr present in the sample. Finally, dividing moles of HBr by the initial volume of the sample (in liters) gives the molar concentration of HBr.
What is the concentration of an HBr solution if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
The reaction between HBr and KOH is a 1:1 ratio. This means that the moles of HBr present in the solution will be equal to the moles of KOH used in the neutralization reaction. Using this information and the volume and concentration of KOH used, you can calculate the concentration of the HBr solution.
