0
What else can I help you with?
How many molecules are there in 45 grams of aluminum triflouride?
To find the number of molecules in 45 grams of aluminum trifluoride (AlF₃), we first need to calculate the molar mass of AlF₃, which is approximately 26.98 g/mol (Al) + 3 × 19.00 g/mol (F) = 83.98 g/mol. Next, we can determine the number of moles in 45 grams by dividing the mass by the molar mass: 45 g / 83.98 g/mol ≈ 0.536 moles. Finally, using Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol), we find the number of molecules: 0.536 moles × (6.022 \times 10^{23}) molecules/mol ≈ (3.22 \times 10^{23}) molecules of AlF₃.
How many molecules are in 26.3 g of calcium hydroxide?
26.3 g of calcium hydroxide contain 2,054 molecules.
How many molecules are in 32 g of SO2?
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
When silver nitrate reacts with barium chloride silver chloride and barium nitrate are formed How many grams of silver chloride are formed when 10.8 g of silver nitrate reacts with 15 g of barium?
9.11 g
How many molecules (not moles) of NH3 are produced from 1.57104 g of H2?
The answer is 1,57.10e27 molecules.
How many molecules are there in 22.0 g of silver chloride?
22.0 g of silver chloride contain 0,918.10e23 molecules.
How many molecules are there in 65 g of silver nitrate?
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
How many molecules are there in 45 grams of aluminum triflouride?
To find the number of molecules in 45 grams of aluminum trifluoride (AlF₃), we first need to calculate the molar mass of AlF₃, which is approximately 26.98 g/mol (Al) + 3 × 19.00 g/mol (F) = 83.98 g/mol. Next, we can determine the number of moles in 45 grams by dividing the mass by the molar mass: 45 g / 83.98 g/mol ≈ 0.536 moles. Finally, using Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol), we find the number of molecules: 0.536 moles × (6.022 \times 10^{23}) molecules/mol ≈ (3.22 \times 10^{23}) molecules of AlF₃.
How many g are in 45 kilogram?
45 kg = 45000 g
How many molecules are there in 65 g of silver nitrate (AgNO3)?
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
How many molecules are in 26.3 g of calcium hydroxide?
26.3 g of calcium hydroxide contain 2,054 molecules.
How many silver atoms are there in g of silver?
2.17*10^22
How many molecules are in 32 g of SO2?
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
When silver nitrate reacts with barium chloride silver chloride and barium nitrate are formed How many grams of silver chloride are formed when 10.8 g of silver nitrate reacts with 15 g of barium?
9.11 g
How many significant figures are in 45 g?
2 of them.
How many molecules (not moles) of NH3 are produced from 1.57104 g of H2?
The answer is 1,57.10e27 molecules.
How many O2 molecules are needed to react with 7.45 g of S?
1,4.10e23 molecules
