To determine the number of molecules in 45 g of silver, you first need to calculate the number of moles of silver using its molar mass (107.87 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
26.3 g of calcium hydroxide contain 2,054 molecules.
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
9.11 g
The answer is 1,57.10e27 molecules.
1,4.10e23 molecules
22.0 g of silver chloride contain 0,918.10e23 molecules.
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
45 kg = 45000 g
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
26.3 g of calcium hydroxide contain 2,054 molecules.
2.17*10^22
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
9.11 g
2 of them.
The answer is 1,57.10e27 molecules.
1,4.10e23 molecules
2