To do this, you need to know the atomic weight of the element you're dealing with, found on any Periodic Table. The atomic weight is the mass in grams of the element in one mole - this will provide you with a conversion factor. So take the measurement in moles and multiply it by the atomic weight to convert to grams. Really what you're doing is dividing the number by 1 mole, and multiplying it by the equivalent of one mole, the atomic weight. That's the thought process behind unit analysis and how you get your "units to cancel".
In this case, the answer is about 34.16 grams He.
The answer is 12,046.1023 molecules.
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
There are approximately 2.41 x 10^23 molecules in 0.400 mol of N2O5. This is calculated by multiplying Avogadro's number (6.022 x 10^23 mol^-1) by the number of moles given.
3.54 (mol) * 6.02*1023 (molecules/mol) = 2.13*1024molecules (of any substance)
To calculate the number of water molecules in 1.802 grams, first find the molar mass of water (H2O = 18.015 g/mol). Then, divide the given mass by the molar mass to get the number of moles (1.802 g / 18.015 g/mol = 0.1 mol). Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of water molecules (0.1 mol * 6.022 x 10^23 molecules/mol = 6.022 x 10^22 molecules).
There are (5.41 \times 10^{23}) molecules of (O_2) in 0.900 moles.
The answer is 12,046.1023 molecules.
There are 6.022x10^23 molecules in 1.00 mol of anything.
There are 3.80 x 10^24 molecules of CO2 in 6.30 mol. This can be calculated by using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
There are approximately 5.8 x 10^24 molecules in 9.6 mol of C2H4. This is calculated using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
The number of molecules is 7,2265690284.10e23.
5.95378*1023
There are 3.505 x 10^23 molecules of H2O in 0.583 mol of H2O, because 1 mol of any substance contains 6.022 x 10^23 molecules.
There are approximately 2.41 x 10^23 molecules in 0.400 mol of N2O5. This is calculated by multiplying Avogadro's number (6.022 x 10^23 mol^-1) by the number of moles given.
2.65 mol * 64.07 g/mol = 169.79 g
1 mole H2O = 6.022 x 1023 molecules 0.357mol H2O x 6.022 x 1023 molecules/mol = 2.15 x 1023 molecules H2O