To find the number of molecules in 30.0 g of CH2O, you first need to calculate the number of moles of CH2O using its molar mass (12.01 g/mol for C, 1.01 g/mol for H, and 16.00 g/mol for O), and then use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
26.3 g of calcium hydroxide contain 2,054 molecules.
The empirical formula CH2O has a molar mass of 30 g/mol (12 g/mol for C + 2 g/mol for H + 16 g/mol for O). To find the molecular formula, which is a multiple of the empirical formula, you divide the molar mass given (180 g/mol) by the empirical formula mass (30 g/mol), giving you 6. Therefore, the molecular formula for the compound is (CH2O)6, which simplifies to C6H12O6, the molecular formula for glucose.
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
The answer is 1,57.10e27 molecules.
1,4.10e23 molecules
To find the number of molecules in 50.0 g of CH2O, you need to first calculate the number of moles of CH2O using its molar mass (30.03 g/mol). Next, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles into molecules. Therefore, 50.0 g of CH2O contains approximately 1.66 x 10^24 molecules.
The number of nitric acid molecules is 28,6723.10e23.
To calculate the mass of 4.55 moles of CH2O, you need to multiply the molar mass of CH2O by the number of moles. The molar mass of CH2O is approximately 30.03 g/mol. Therefore, the mass of 4.55 moles of CH2O is 136.665 g.
The empirical formula CH2O has a molar mass of 30.03 g/mol (12 g/mol for C + 2 g/mol for H + 16 g/mol for O). To find the molecular formula, divide the molar mass given (120.1 g/mol) by the molar mass of the empirical formula to get 4. This means the molecular formula is (CH2O)4, which simplifies to C4H8O4.
To find the number of moles in 31 grams of CH2O, we divide the mass by the molar mass of CH2O (30.03 g/mol). This gives us approximately 1.03 moles of CH2O. Since there are two hydrogen atoms in each molecule of CH2O, we multiply the number of moles by Avogadro's number (6.02 x 10^23) and by 2 to find about 1.24 x 10^24 hydrogen atoms.
22.0 g of silver chloride contain 0,918.10e23 molecules.
26.3 g of calcium hydroxide contain 2,054 molecules.
The empirical formula CH2O has a molar mass of 30 g/mol (12 g/mol for C + 2 g/mol for H + 16 g/mol for O). To find the molecular formula, which is a multiple of the empirical formula, you divide the molar mass given (180 g/mol) by the empirical formula mass (30 g/mol), giving you 6. Therefore, the molecular formula for the compound is (CH2O)6, which simplifies to C6H12O6, the molecular formula for glucose.
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
1,4.10e23 molecules
The answer is 1,57.10e27 molecules.
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