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To find the number of moles in a 500 cm³ (or 0.500 L) solution of lithium bromide (LiBr) with a concentration of 5.0 M, you can use the formula:
[ \text{Moles} = \text{Molarity} \times \text{Volume (L)} ]
Substituting the values gives:
[ \text{Moles} = 5.0 , \text{M} \times 0.500 , \text{L} = 2.5 , \text{moles} ]
Therefore, there are 2.5 moles of lithium bromide in the solution.
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How many litters of 4M solution can be made using 100 grams of lithium bromide?
To determine how many liters of a 4M lithium bromide (LiBr) solution can be made from 100 grams of LiBr, we first need to calculate the number of moles in 100 grams. The molar mass of lithium bromide is approximately 86.84 g/mol, so 100 grams corresponds to about 1.15 moles. A 4M solution contains 4 moles of solute per liter, thus 1.15 moles can produce approximately 0.29 liters (1.15 moles ÷ 4 moles/L). Therefore, 100 grams of lithium bromide can make about 0.29 liters of a 4M solution.
How many moles of Lithium carbonate are needed to make a concentration of 12.7M in a 5 L solution Answer?
To find the number of moles of lithium carbonate needed for a 12.7 M concentration in a 5 L solution, use the formula: moles = concentration (M) × volume (L). Thus, moles = 12.7 M × 5 L = 63.5 moles. Therefore, 63.5 moles of lithium carbonate are required.
What is the molarity of a solution that contains 4.53 moles of lithium nitrate in 2.85 liters of solution?
This molarity is 1,59.
How many atoms are found in 10 moles of LiBr?
10 moles LiBr (6.022 X 1023/1 mole LiBr)= 6.022 X 1024 atoms of lithium bromide=========================
What is the molarity of a solution that contains 1.1 moles of lithium in 0.5-liters of solution?
Molarity is moles per litre. You need to multiply moles per 0.5 litres by 2. Doing this gives you 2.2 moles per litre, i.e. 2.2 molar.
How many grams of lithium bromide are present in 25.0 mL of a 0.100 M soution?
To calculate the grams of lithium bromide present in the solution, you would first determine the moles of lithium bromide using the formula: moles = Molarity x Volume (L). Once you have the moles, you can convert it to grams using the molar mass of lithium bromide (86.85 g/mol).
How many litters of 4M solution can be made using 100 grams of lithium bromide?
To determine how many liters of a 4M lithium bromide (LiBr) solution can be made from 100 grams of LiBr, we first need to calculate the number of moles in 100 grams. The molar mass of lithium bromide is approximately 86.84 g/mol, so 100 grams corresponds to about 1.15 moles. A 4M solution contains 4 moles of solute per liter, thus 1.15 moles can produce approximately 0.29 liters (1.15 moles ÷ 4 moles/L). Therefore, 100 grams of lithium bromide can make about 0.29 liters of a 4M solution.
How many moles of lithium chloride will be formed by the reaction of chlorine with 0.046 mol of lithium bromide in the following reaction?
The balanced chemical equation for the reaction is: 2LiBr + Cl2 -> 2LiCl + Br2 Since the ratio of lithium bromide to lithium chloride is 1:1, 0.046 mol of lithium bromide will produce 0.046 mol of lithium chloride.
How many moles of Lithium chloride need to be added to one liter of total solution to make up a 1.25 M solution?
To make a 1.25 M solution of lithium chloride in one liter of total solution, you need 1.25 moles of lithium chloride. This is because the concentration of a solution in moles per liter is equal to the number of moles of solute divided by the volume of the solution in liters.
How many moles of bromide ions are present in 750.0 mL of 1.35 M MgBr2?
There are 1.35 moles of MgBr2 in 1 L of solution, which corresponds to 2 moles of bromide ions. Therefore, in 750.0 mL of 1.35 M MgBr2 solution, there will be 1.0125 moles of bromide ions.
What volume of 0.256 M sodium bromide contains 18.7 grams of bromide?
Need moles sodium bromide first. 18.7 grams NaBr (1 mole NaBr/102.89 grams) = 0.1817 moles NaBr =====================Now, Molarity = moles of solute/Liters of solution 0.256 M NaBr = 0.1817 moles NaBr/X Liters Liters = 0.1817/0.256 = 0.7098 Liters -------------------------( you do sigi figis )
How many moles of lithium chloride will be formed by the reaction of chlorine with 046 moles of lithium bromide in the following reaction 2 LiBr plus Cl2 equals 2 LiCI plus Br2?
2LiBr(aq) + Cl2(g) = 2LiCl(aq) + Br2(l) will result in .167 moles of lithium chloride.
Molarity of 734 grams of lithium sulfate are dissolved to make 2500ml of solution?
To find the molarity of the solution, first calculate the number of moles of lithium sulfate in 734g. Then, divide the moles by the volume of solution in liters to get the molarity. Remember to convert grams to moles using the molar mass of lithium sulfate (Li2SO4).
How many moles of Lithium carbonate are needed to make a concentration of 12.7M in a 5 L solution Answer?
To find the number of moles of lithium carbonate needed for a 12.7 M concentration in a 5 L solution, use the formula: moles = concentration (M) × volume (L). Thus, moles = 12.7 M × 5 L = 63.5 moles. Therefore, 63.5 moles of lithium carbonate are required.
How many moles of bromide are there in Iron Bromide?
To determine how many moles of bromide are in iron (III) bromide (FeBr3), you can use the chemical formula FeBr3 to see that there are three moles of bromide ions for every mole of iron (III) bromide. So, the number of moles of bromide ions is equal to the number of moles of FeBr3.
What is the molarity of 200 ml of solution which 2.0 moles of sodium bromide is dissolved?
So molarity means moles per litre. but you don't have a litre. if you did you'd have 1000/200 times the moles that you have. 2 moles / 200 x 1000 is 10 moles. As it is per litre, it is 2 molar.
What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium flouride?
The molarity of the solution can be calculated by first finding the moles of lithium fluoride using its molar mass, which is 25.94 g/mol for lithium and 19.00 g/mol for fluorine. Add these together to find the molar mass of lithium fluoride. Then, divide the mass of lithium fluoride by its molar mass to get the moles. Finally, divide the moles by the volume of the solution in liters to get the molarity.
