0.00512615466634
10 g platinum is equal to 0,05 moles.
The standard atomic weight of platinum is 195,084 g.195,084 g-------------------------------1 mol250 g-------------------------------------x molx = 250/195,084 = 1,28 mol platinum
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
10 g platinum is equal to 0,05 moles.
To find the number of moles of platinum in 10g, divide the mass by the molar mass of platinum. The molar mass of platinum is approximately 195.08 g/mol. Therefore, there are 0.051 moles of platinum in 10g.
The standard atomic weight of platinum is 195,084 g.195,084 g-------------------------------1 mol250 g-------------------------------------x molx = 250/195,084 = 1,28 mol platinum
To find the mass of 0.48 moles of platinum, you would multiply the number of moles by the molar mass of platinum. The molar mass of platinum is approximately 195.08 g/mol, so the mass of 0.48 moles of platinum would be 0.48 moles * 195.08 g/mol ≈ 93.62 grams.
To determine the number of atoms in 97.6g of platinum, you first need to calculate the number of moles of platinum using its molar mass (195.08 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of platinum to atoms. This calculation will give you the total number of atoms in 97.6g of platinum.
9.0 grams divides by its molar mass: 195.1 g/mol9.0 / 195.1 = 0.046 mol
The formula is: number of moles = g Be/9,012.
978 g calcium contain 24,4 moles.
29,0 g of calcium is equal to 0,723 moles.
67,4 g HCl is equivalent to 1,85 moles.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.