It depends on how much you have.
K2CrO4 Molarity (concentration) = moles of solute/Liters of solution (100 ml = 0.100 Liters ) Find moles K2CrO4 first. 3.50 grams = (1 mole K2CrO4/194.2 grams) = 0.01802 moles K2CrO4 ----------------------------------------------next Molarity = 0.01802 moles K2CrO4/0.100 Liters = 0.180 M K2CrO4 -------------------------
The Molarity is equal to the number of moles divided by the liters. M=mol/L M=0.120 mol/5.0 L M=0.024 so the molarity is 0.024 M
16 grams of oxygen how many moles is 0,5 moles.
moles of what?
No, K2CrO4 (potassium chromate) is an inorganic compound. Organic compounds contain carbon atoms bonded to hydrogen atoms, while inorganic compounds do not.
K2CrO4 Molarity (concentration) = moles of solute/Liters of solution (100 ml = 0.100 Liters ) Find moles K2CrO4 first. 3.50 grams = (1 mole K2CrO4/194.2 grams) = 0.01802 moles K2CrO4 ----------------------------------------------next Molarity = 0.01802 moles K2CrO4/0.100 Liters = 0.180 M K2CrO4 -------------------------
The molar mass of K2CrO4 is 294.18 g/mol. Therefore, the number of moles of K2CrO4 in 414.4 mg is 0.00141 mol. As there are 2 moles of chromium in 1 mole of K2CrO4, the number of moles of chromium is 0.00282 mol. The concentration of chromium in the stock solution is 28,200 ppm.
The chemical formula for potassium chromate is K2CrO4.
The dissociation equation for potassium chromate (K2CrO4) in water is: K2CrO4(s) -> 2K+(aq) + CrO4^2-(aq).
KCrO4 does not exist it is K2CrO4 and is called Potassium Chromate. Potassium dichromate is K2Cr2O7
To make a 0.25N K2CrO4 solution, you need to first calculate the molecular weight of K2CrO4 (potassium chromate). Then, determine the grams of K2CrO4 needed to make the desired volume of solution at a concentration of 0.25N. Dissolve this amount of K2CrO4 in the required volume of solvent, usually water, to make the final solution.
Potassium chromate (K2CrO4) is a yellow colored compound.
The Molarity is equal to the number of moles divided by the liters. M=mol/L M=0.120 mol/5.0 L M=0.024 so the molarity is 0.024 M
BaCl2+K2CrO4--------->BaCrO4+2KCl BaCrO4 is a yellow precipitate.
The ion for K2CrO4 is the chromate ion, which has a chemical formula of CrO4^2-.
Formula: K2CrO4
Formula: K2CrO4