0
74 g magnesium (1 mole Mg/24.31 g)(6.022 X 1023/1 mole Mg)(1 mole Mg atoms/6.022 X 1023)
= 3.0 moles of magnesium atoms
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As you see Avogadro's number is over itself as a form of one, so only the moles of Mg need be found. This depiction is the formal set up.
What else can I help you with?
You have a sample of 1.25 g of magnesium hydroxide MgOH 2 How many moles of magnesium hydroxide are there?
0.0214 mol
How many moles in 20g of magnesium nitrate?
There are 0.13 moles in 20 grams of magnesium nitrate.
How many moles are in 8 grams of sodium hydroxide?
0.2 mol
How many grams are in 5.2 moles of magnesium sulfide?
Mass in grams = no of moles x molecular mass. So, mass in grams = 5.2x 56 = 291.2g
How many atoms of oxygen are in 3.33 grams of magnesium hydroxide?
first work out how many moles of Mg(OH)2 you have. n = m /M = 3.33 / 58 = 0.0574 mol Then from this work out how many mol of O you have. there are two oxygens in the formula so you have 0.0574 x 2 mol of O = 0.1148 mol 1 mol = 6.023x 1023 particles. So 6.023 x 10 23 /1 x 0.1148 = 6.92 x 10 22
How many grams are in 1.11 moles of magnesium?
1,11 moles of magnesium have 26,97855 g.
You have a sample of 1.25 g of magnesium hydroxide MgOH 2 How many moles of magnesium hydroxide are there?
0.0214 mol
How many moles in 20g of magnesium nitrate?
There are 0.13 moles in 20 grams of magnesium nitrate.
How many moles are in 88.1 grams of magnesium?
88,1 moles of magnesium is equivalent to 2 141,27 g.
How many grams of magnesium hydroxide required to make 1M of the solution?
the formula is no. moles is mass / molecular mass. As the number of moles is 1, the mass required will be exactly the same as the molecular mass, which is 58.32g
How many moles are in 8 grams of sodium hydroxide?
0.2 mol
How many moles in 13.5 grams of magnesium nitrate?
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
How many grams are in 5.2 moles of magnesium sulfide?
Mass in grams = no of moles x molecular mass. So, mass in grams = 5.2x 56 = 291.2g
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
How many grams of water are needed to produce one hundred fifty grams of magnesium hydroxide?
A lot
How many atoms of oxygen are in 3.33 grams of magnesium hydroxide?
first work out how many moles of Mg(OH)2 you have. n = m /M = 3.33 / 58 = 0.0574 mol Then from this work out how many mol of O you have. there are two oxygens in the formula so you have 0.0574 x 2 mol of O = 0.1148 mol 1 mol = 6.023x 1023 particles. So 6.023 x 10 23 /1 x 0.1148 = 6.92 x 10 22
How many grams are in 88.1 moles of magnesium?
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
