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How many moles of calcium represent in 120 grams?
120 g calcium is equal to 3 moles.
How many grams of glucose are in 3.55 moles of glucose?
3,50 moles of glucose is equal to 630,56 g.
How many number of moles of atom are present in 540 grams of glucose?
To find the number of moles of glucose (C₆H₁₂O₆) in 540 grams, first calculate the molar mass of glucose: (6 × 12.01) + (12 × 1.008) + (6 × 16.00) = 180.18 g/mol. Then, use the formula: moles = mass (g) / molar mass (g/mol). Thus, the number of moles in 540 grams of glucose is 540 g / 180.18 g/mol ≈ 3.00 moles.
How many molecules are present in 936 g of glucose (c6h12o6)?
To find the number of molecules in 936 g of glucose (C₆H₁₂O₆), first calculate the molar mass of glucose, which is approximately 180.18 g/mol. Next, use the formula: number of moles = mass (g) / molar mass (g/mol). Thus, 936 g of glucose corresponds to about 5.19 moles. Finally, multiplying the moles by Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol) gives roughly (3.12 \times 10^{24}) molecules of glucose.
How many milimoles are in 35 grams of glucose?
The molar mass of glucose is 180,16 grams.180,16 g------------1 mol35 g------------------xX = 0,194 moles or 194 millimoles
How many grams are in 2.7 moles of glucose?
2.,7 moles of glucose have 486,432 g.
How many moles of calcium represent in 120 grams?
120 g calcium is equal to 3 moles.
How many grams of glucose are in 3.55 moles of glucose?
3,50 moles of glucose is equal to 630,56 g.
How many number of moles of atom are present in 540 grams of glucose?
To find the number of moles of glucose (C₆H₁₂O₆) in 540 grams, first calculate the molar mass of glucose: (6 × 12.01) + (12 × 1.008) + (6 × 16.00) = 180.18 g/mol. Then, use the formula: moles = mass (g) / molar mass (g/mol). Thus, the number of moles in 540 grams of glucose is 540 g / 180.18 g/mol ≈ 3.00 moles.
How many moles of glucose are required to form 127g of ethanol?
To form ethanol, the chemical equation shows that one mole of glucose is converted to two moles of ethanol. The molar mass of glucose is around 180 g/mol and that of ethanol is around 46 g/mol. Therefore, to produce 127g of ethanol, you would need 127g/(46g/mol) = 2.76 moles of ethanol. Since glucose to ethanol is a 1:2 ratio, you would need half as many moles of glucose, which would be 1.38 moles of glucose.
How many molecules are present in 936 g of glucose (c6h12o6)?
To find the number of molecules in 936 g of glucose (C₆H₁₂O₆), first calculate the molar mass of glucose, which is approximately 180.18 g/mol. Next, use the formula: number of moles = mass (g) / molar mass (g/mol). Thus, 936 g of glucose corresponds to about 5.19 moles. Finally, multiplying the moles by Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol) gives roughly (3.12 \times 10^{24}) molecules of glucose.
How many milimoles are in 35 grams of glucose?
The molar mass of glucose is 180,16 grams.180,16 g------------1 mol35 g------------------xX = 0,194 moles or 194 millimoles
How many moles are in 817g of sodium phosphate?
n = 817 g x (1 mol / 120 g) = 6.81 mol
A solution contains 180g of glucose C6H12O6 and 162 g of water What is the mole fraction of glucose?
To calculate the mole fraction of glucose, first find the moles of each component by dividing its mass by its molar mass. The molar mass of glucose (C6H12O6) is 180 g/mol. The moles of glucose is 180g / 180 g/mol = 1 mol. The moles of water is 162g / 18 g/mol = 9 mol. The total moles in the solution is 1 + 9 = 10 mol. The mole fraction of glucose is 1 mol / 10 mol = 0.1.
How many molecules are present in 936 g of glucose?
To find the number of molecules present in 936 g of glucose, you would first calculate the number of moles of glucose using its molecular weight. Then, you would use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many grams of glucose are contained in 555 mL of a 1.77 M glucose solution?
To find the grams of glucose in a 555 mL solution of 1.77 M concentration, first convert the volume to liters: 555 mL = 0.555 L. Then, use the molarity formula, which states that moles of solute = molarity × volume in liters. Thus, the moles of glucose = 1.77 mol/L × 0.555 L = 0.9835 moles. Finally, convert moles to grams using the molar mass of glucose (approximately 180.18 g/mol): 0.9835 moles × 180.18 g/mol ≈ 177.3 grams of glucose.
What is the mass of 4.00 moles of sugar formula of sugar C6H12O6?
C6H12O6 is the chemical formula of glucose (not sucrose !).The mass of 4.00 moles of glucose is 720,64 g.
