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To find the number of moles in 3.00 g of ethanol (C₂H₅OH), first calculate its molar mass. The molar mass of ethanol is approximately 46.07 g/mol. Using the formula ( \text{moles} = \frac{\text{mass}}{\text{molar mass}} ), we have ( \text{moles} = \frac{3.00 , \text{g}}{46.07 , \text{g/mol}} \approx 0.065 , \text{moles} ). Thus, there are approximately 0.065 moles of ethanol in 3.00 g.
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How many moles in 300g of sulfur?
300 g sulfur is equivalent to 9,357 moles.
Please show work How many moles would there be in 300 ml of of a 1.5 M solution?
To find the number of moles, use the formula: moles = Molarity (M) x Volume (L). First, convert 300 ml to liters by dividing by 1000: 300 ml / 1000 = 0.3 L. Then, calculate moles = 1.5 M x 0.3 L = 0.45 moles. Therefore, there would be 0.45 moles in 300 ml of a 1.5 M solution.
How do I convert 300 moles of N2 to kiloliters?
300 moles of nitrogen equals 8404,2 g.The density of nitrogen at 20 oc and 1 at is 1,251 g/cm3.8404,2 g nitrogen equals 6 718 L.1 kL = 1 000 LSo the volume of 300 moles N2 is 6,718 kL.
What volume is needed to store 0.08 moles of helium gas at 204.67 KP and 300 k?
This is very easy. you need 9.752l for that.
If you have 17 moles of gas at a temperature of 67 degrees Celsius and a volume of 25 liters and a temperature of 300 K how many moles of as do you have?
Using the ideal gas law, you can calculate the number of moles of gas using the formula PV = nRT. First, convert the initial temperature of 67 degrees Celsius to Kelvin by adding 273 to it, which gives 340 K. Then apply the formula with the initial conditions to solve for n, which would be approximately 11 moles of gas.
How many moles in 300g of sulfur?
300 g sulfur is equivalent to 9,357 moles.
Approximately how many moles are in 300 grams of sulfur?
To determine the number of moles in 300 grams of sulfur, you need to know the molar mass of sulfur. The molar mass of sulfur is 32.06 g/mol. You can calculate the number of moles by dividing the given mass by the molar mass: 300 g / 32.06 g/mol ≈ 9.35 moles.
Please show work How many moles would there be in 300 ml of of a 1.5 M solution?
To find the number of moles, use the formula: moles = Molarity (M) x Volume (L). First, convert 300 ml to liters by dividing by 1000: 300 ml / 1000 = 0.3 L. Then, calculate moles = 1.5 M x 0.3 L = 0.45 moles. Therefore, there would be 0.45 moles in 300 ml of a 1.5 M solution.
How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
How many moles of potassium hydroxide are required to prepare 300 mL of 0.250 M solution?
To calculate the moles of potassium hydroxide needed, use the formula: moles = molarity * volume (in liters). First, convert 300 mL to liters (0.3 L). Then, moles = 0.250 mol/L * 0.3 L = 0.075 moles of potassium hydroxide needed to prepare the solution.
How many gallons of ethanol are produced from an acre of corn?
Generally speaking about 300 gallons per acre.
How many moles are in 300 grams of calcium sulfide?
To determine the number of moles in 300 grams of calcium sulfide, first calculate the molar mass of calcium sulfide (CaS). The molar mass of CaS is 40.08 g/mol (for calcium) + 32.06 g/mol (for sulfur), which equals 72.14 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 300 g / 72.14 g/mol ≈ 4.16 moles.
How many grams of sodium chloride is in 0.40 moles?
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
300 g of ammonia react with 36 moles of sulfuric acid to produce ammonia sulfate how many moles of excess sulfuric acid are left over after the reaction is complete?
26.9 - 27.4
How many millimoles are in 12g of sodium hydroxide?
The molecular weight of sodium hydroxide is 40g/mol. To get the amount of moles, you have to divide the weight by molecular mass. 12g / 40 is 0.3 moles. This is 300 millimoles.
What is the molarity of a 3000 liters solution containing 300 grams of NaCl?
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
How far do Moles tunnel in a day?
1 foot
