48,5 g sample of CS2 is the equivalent of 0,637 moles.
The balanced chemical equation is ( 5C(s) + 2SO_2(g) \rightarrow CS_2(l) + 4CO(g) ). According to the stoichiometry of the reaction, 5 moles of carbon (C) react with 2 moles of sulfur dioxide (SO₂). To find the moles of C needed for 0.480 moles of SO₂, use the ratio ( \frac{5 , \text{moles C}}{2 , \text{moles SO}_2} ). Therefore, the moles of C required are ( 0.480 , \text{moles SO}_2 \times \frac{5 , \text{moles C}}{2 , \text{moles SO}_2} = 1.20 , \text{moles C} ).
To determine how many moles of SO₂ are required to produce 118 grams of CS₂, we first need to know the molar mass of CS₂, which is approximately 76.14 g/mol. By dividing the mass of CS₂ (118 g) by its molar mass, we find that 1.55 moles of CS₂ are produced. The balanced chemical equation for the reaction is ( \text{C} + 2\text{S} + \text{O}_2 \rightarrow \text{CS}_2 + 2\text{SO}_2 ), indicating that for every mole of CS₂ produced, 2 moles of SO₂ are required. Therefore, 1.55 moles of CS₂ will need 3.1 moles of SO₂.
No, carbon disulfide (CS2) is not miscible in water. This is because CS2 is a nonpolar compound while water is a polar molecule. Nonpolar and polar molecules do not mix easily due to their differing intermolecular forces.
cs2 does nota dipole momentbecause it is liner
The enthalpy of formation of carbon disulfide (CS2) can be indicated by the reaction: C(s) + 2 S(s) → CS2(l). This reaction represents the formation of one mole of CS2 from its elements in their standard states. The enthalpy change associated with this reaction is +89.4 kJ/mol, meaning that 89.4 kJ of energy is absorbed when one mole of CS2 is formed from solid carbon and solid sulfur.
4.2 moles of CS2 contain 8,4 moles sulfur.
To find the number of moles in 19.2 g of CS2, we need to divide the given mass by the molar mass of CS2. The molar mass of CS2 is 76.14 g/mol. So, 19.2 g ÷ 76.14 g/mol ≈ 0.252 moles of CS2.
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
6. 1 mole of CS2 contains 1 mole of carbon and 2 of sulfur.
For this you need the atomic (molecular) mass of CS2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CS2=76.2 grams10.00 moles CS2 × (76.2 grams) = 762 grams CS2
To determine the amount of CS2 that can be produced from 100 grams of S8, we need to first convert 100 grams of S8 to moles using the molar mass of S8 and then use the balanced chemical equation to find the moles of CS2 produced. Finally, we convert moles of CS2 to grams using the molar mass of CS2.
The balanced chemical equation for the reaction is: C + 2SO2 → CS2 + 2O2. From the equation, 1 mole of carbon produces 1 mole of CS2. Therefore, if 5.9 moles of carbon react, 5.9 moles of CS2 are produced.
1.2 Moles
The chemical equation for the combustion of carbon disulfide (CS2) is: CS2 + 3O2 -> CO2 + 2SO2. From the balanced equation, 2 moles of CS2 will produce 2 moles of SO2. The volume of SO2 gas formed will depend on the temperature, pressure, and volume of the reaction, as well as the ideal gas law equation (PV = nRT).
The balanced chemical equation shows that 1 mole of coke reacts with 1 mole of sulfur dioxide to produce 1 mole of carbon disulfide. Therefore, if 8.0 moles of coke react, then 8.0 moles of carbon disulfide will be generated.
The balanced chemical equation for the reaction between carbon (C) and sulfur dioxide (SO2) is C + 2SO2 -> CS2 + 2O2. From the equation, 1 mole of C reacts with 2 moles of SO2. Therefore, you would need 0.255 moles of C to react with 0.510 moles of SO2.
the chemical formula for carbon disulfide is CS2.