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The answer is 0,253 moles.

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13y ago

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How many moles in a 48.5 g sample of CS2?

48,5 g sample of CS2 is the equivalent of 0,637 moles.


How many grams of CS2 are present in 10.00 moles?

For this you need the atomic (molecular) mass of CS2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CS2=76.2 grams10.00 moles CS2 × (76.2 grams) = 762 grams CS2


When carbon disulfide is formed from its elements heat is absorbed Calculate the amount of heat in kJ absorbed when 5.66g of carbon disulfied is formed?

The molar mass of carbon disulfide (CS2) is 76.14 g/mol. To calculate the moles of CS2 in 5.66 g, divide the mass by the molar mass: 5.66 g / 76.14 g/mol = 0.074 moles. Since heat is absorbed when CS2 is formed, we know this process is endothermic. You will need to know the molar enthalpy of formation (ΔHf) of carbon disulfide to calculate the amount of heat absorbed.


How many grams of aluminum are needed to react with 192 g of oxygen gas?

First determine the balanced chemical reaction:4Al + 3O2 ---> 2Al2O3Next figure out the number of moles of oxygen you start with by dividing 192 by the molecular weight of oxygen (16 g/mol). Then use the coefficients from the reaction to determine how many moles of Al would need to react with the oxygen to convert all the oxygen and aluminum to aluminum oxide.192 g * (1 mol O / 16 g O) * (4 moles of Al/6 moles of O) = 8 mol of AlFinally multiply by the molecular weight of Aluminum to figure out the mass:8 mol Al * (27 g/mol) = 216 g of Al


If you have g of beryllium how many moles is this equivalent to?

The formula is: number of moles = g Be/9,012.


How many moles are in 14.84 g Mg?

14,84 g magnesium are equivalent to 0,61 moles.


How many moles are in 97.5 g of oxygen?

97,5 g of oxygen is equal to 5,416 moles.


How many moles are in 978 g Ca?

978 g calcium contain 24,4 moles.


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67,4 g HCl is equivalent to 1,85 moles.


How many moles are in 29.0 g of calcium?

29,0 g of calcium is equal to 0,723 moles.


How many moles is 573.28 g of AgCI?

573,28 of g of AgCI is equivalent to 4 moles.


How many moles are in 27.4 g of water?

27.4 g H2O x 1 mole/18 g = 1.52 moles