The answer is 0,253 moles.
The molar mass of carbon disulfide (CS2) is 76.14 g/mol. To calculate the moles of CS2 in 5.66 g, divide the mass by the molar mass: 5.66 g / 76.14 g/mol = 0.074 moles. Since heat is absorbed when CS2 is formed, we know this process is endothermic. You will need to know the molar enthalpy of formation (ΔHf) of carbon disulfide to calculate the amount of heat absorbed.
27.4 g H2O x 1 mole/18 g = 1.52 moles
To calculate the number of moles in 100mg of citric acid (C6H8O7), first determine its molar mass by adding up the atomic masses of each element: C(12.01) + H(1.01) + O(16.00) x 7. Convert 100mg to grams (0.1g) and then divide the mass by the molar mass of citric acid to find the number of moles.
To find the number of moles in 4.5 g of AgNO3, you first need to determine the molar mass of AgNO3 which is 169.87 g/mol. Then you can use the formula: moles = mass / molar mass. Therefore, moles = 4.5 g / 169.87 g/mol ≈ 0.0265 moles.
To find the number of moles, you need to divide the given mass (in grams) by the molar mass of CCl4, which is 153.82 g/mol. Therefore, 56 g / 153.82 g/mol = 0.364 moles of CCl4.
48,5 g sample of CS2 is the equivalent of 0,637 moles.
For this you need the atomic (molecular) mass of CS2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CS2=76.2 grams10.00 moles CS2 × (76.2 grams) = 762 grams CS2
The molar mass of carbon disulfide (CS2) is 76.14 g/mol. To calculate the moles of CS2 in 5.66 g, divide the mass by the molar mass: 5.66 g / 76.14 g/mol = 0.074 moles. Since heat is absorbed when CS2 is formed, we know this process is endothermic. You will need to know the molar enthalpy of formation (ΔHf) of carbon disulfide to calculate the amount of heat absorbed.
First determine the balanced chemical reaction:4Al + 3O2 ---> 2Al2O3Next figure out the number of moles of oxygen you start with by dividing 192 by the molecular weight of oxygen (16 g/mol). Then use the coefficients from the reaction to determine how many moles of Al would need to react with the oxygen to convert all the oxygen and aluminum to aluminum oxide.192 g * (1 mol O / 16 g O) * (4 moles of Al/6 moles of O) = 8 mol of AlFinally multiply by the molecular weight of Aluminum to figure out the mass:8 mol Al * (27 g/mol) = 216 g of Al
The formula is: number of moles = g Be/9,012.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
67,4 g HCl is equivalent to 1,85 moles.
29,0 g of calcium is equal to 0,723 moles.
573,28 of g of AgCI is equivalent to 4 moles.
27.4 g H2O x 1 mole/18 g = 1.52 moles