First you need to know the molecular mass of the compound. The molecular mass is the sum of the atomic masses of each atom in the molecule. This means that you need to count atoms of the same element each time they occur in the compound.
Carbon = 12.0 × 5 atoms = 60.0 grams
Hydrogen = 1.0 × 12 atoms = 12.0 grams
________________________________________
Pentane = 72.0 grams
Now we take the mass in grams and convert it to moles using the formula:
# grams ÷ molecular mass = # moles
220 g ÷ 72.0 g = 3.06 moles pentane
5.60 g C6H12O6 (1 mole C6H12O6/180.156 g)(6 moles C/1 mole C6H12O6)(6.022 X 1023/1 mole C) = 1.12 X 1023 atoms of carbon ======================
There are 24 moles of Carbon (C) in 2 moles of table sugar (sucrose)
To determine the number of carbon atoms in 7.11g of glucose, you first need to calculate the moles of glucose using its molar mass. The molar mass of glucose (C6H12O6) is 180.16 g/mol. Next, calculate the number of moles of carbon in one mole of glucose (6 moles). Finally, multiply the moles of glucose by the number of moles of carbon to find the total number of carbon atoms in 7.11g of glucose.
The answer is 2,17 moles carbon.
The reaction is:2 C + O2 = 2 COSo 2,1 moles are obtained.
5.60 g C6H12O6 (1 mole C6H12O6/180.156 g)(6 moles C/1 mole C6H12O6)(6.022 X 1023/1 mole C) = 1.12 X 1023 atoms of carbon ======================
There are 24 moles of Carbon (C) in 2 moles of table sugar (sucrose)
C6H1206 has 6 Carbon atoms, 12 Hydrogen atoms, and 6 Oxygen atoms, otherwise known as Glucose, a plant food made for long-term storage. Sorry if that's not what you're looking for! Added: This is what you are looking for. 300 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 mole C/1 mole C6H12O6)(6.022 X 10^23/1 mole C)(1 mole C/6.022 X 10^23) = 9.99 moles Carbon atoms in that mass glucose 300 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(12 mole H/1 mole C6H12O6)(6.022 X 10^23/1 mole H)(1 mole H/6.022 X 10^23) = 19.98 moles Hydrogen atoms in that mass glucose Now, you have seen two examples of this procedure, so you do the oxygen number crunching.
To determine the number of carbon atoms in 7.11g of glucose, you first need to calculate the moles of glucose using its molar mass. The molar mass of glucose (C6H12O6) is 180.16 g/mol. Next, calculate the number of moles of carbon in one mole of glucose (6 moles). Finally, multiply the moles of glucose by the number of moles of carbon to find the total number of carbon atoms in 7.11g of glucose.
The answer is 2,17 moles carbon.
How many moles of C are needed to react with 0.490 mole SO2?
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
There are 3 elements in the compound C6H12O6: carbon (C), hydrogen (H), and oxygen (O).
The reaction is:2 C + O2 = 2 COSo 2,1 moles are obtained.
The combustion of butane (C₄H₁₀) can be represented by the balanced equation: 2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O. From this equation, we see that 2 moles of butane produce 8 moles of carbon dioxide. Therefore, if 5.31 moles of C₄H₁₀ are used, the moles of CO₂ produced can be calculated as follows: (5.31 moles C₄H₁₀) × (8 moles CO₂ / 2 moles C₄H₁₀) = 21.24 moles of CO₂.
1,4 moles carbon monoxide are produced.
4,37.10e-18 C atoms are equivalent to 7,25.10e-6 moles.