In 1 mole of lithium hydride (LiH), there is 1 mole of lithium (Li) present. This is because the chemical formula indicates that each molecule of LiH consists of one lithium atom and one hydrogen atom. Therefore, if you have 1 mole of LiH, it contains exactly 1 mole of Li.
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
To determine the number of moles of water needed to react with 1.7 moles of Li2O, we can use the balanced chemical equation for the reaction: [ \text{Li}_2\text{O} + 2\text{H}_2\text{O} \rightarrow 2\text{LiOH}. ] From the equation, 1 mole of Li2O reacts with 2 moles of water. Therefore, 1.7 moles of Li2O would require 1.7 x 2 = 3.4 moles of water.
1 mole Li = 6.94g Li = 6.022 x 1023 atoms Li 27.0g Li x 6.022 x 1023 atoms Li/6.94g Li = 2.34 x 1024 atoms Li
20,32 g of lithium nitride can be obtained.
The reaction between lithium (Li) and water (H₂O) produces lithium hydroxide (LiOH) and hydrogen gas (H₂). The balanced chemical equation for this reaction is: [ 2 \text{Li} + 2 \text{H}_2\text{O} \rightarrow 2 \text{LiOH} + \text{H}_2 ] In this equation, two moles of lithium react with two moles of water to produce two moles of lithium hydroxide and one mole of hydrogen gas, ensuring that both mass and charge are conserved.
1 mole of Li₂O contains 2 moles of lithium (Li) atoms and 1 mole of oxygen (O) atoms. Therefore, in 1 mole of Li₂O, there are a total of 3 moles of atoms.
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
From the periodic table, lithium has an atomic weight of 6.941. The molar mass of an element is the atomic weight in grams. Therefore, 1 mole Li = 6.941g Li Therefore, moles Li = 15g Li X 1 mole Li/6.941g Li = 2.2 moles Li
4.7 mole Li (6.022 X 10^23/1 mole Li) = 2.8 X 10^24 atoms Li
The balanced chemical equation for the reaction is 3Li + H3PO4 -> Li3PO4 + 3H2. The mole ratio is 1:1 between Li and H3PO4. Therefore, 4 moles of H3PO4 will react with 4 moles of Li.
3,00 moles of Li have 18,066422571.10e23 atoms.
(7.6g LiBr)/(86.84g/mol) x (1molLi/1molBr) = .0875 mol Li or with sig figs, .088
This reaction? 6Li + N2 --> 2Li3N 0.450 moles Li (2 moles Li3N/6 moles Li) = 0.150 moles lithium nitride produced ===========================
15g Li * (1mol Li / 6.941g Li) = 2.16 mol Li
For this problem, the atomic mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.2.5 moles H2 × (6.02 × 1023 atoms) = 1.51 × 1024 atoms
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
No moles of BaCO3 are found in any amount of Li.