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To find the number of moles of MgS₂O₃ in 209 grams, you first need to calculate the molar mass of MgS₂O₃. The molar mass is approximately 120.37 g/mol (Mg: 24.31 g/mol, S: 32.07 g/mol x 2, O: 16.00 g/mol x 3). Then, divide the mass of the compound by its molar mass: ( \text{moles} = \frac{209 \text{ g}}{120.37 \text{ g/mol}} \approx 1.74 ) moles.
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How many grams are needed to have 5.00 moles?
This depends on the compound.
How many grams of phosphorus trichloride are present in 3.42 moles of this compound?
3,42 moles of phosphorus trichloride have 469,6686 g.
If compound A has a molar mass of 159.7 gmole and compound C has a molar mass of 57.6 gmole how many grams of compound C will be produced from 17.62 grams of compound A and excess compound B?
To determine the grams of compound C produced from 17.62 grams of compound A, we first need to calculate the number of moles of compound A. This is done by dividing the mass of compound A by its molar mass: ( \text{moles of A} = \frac{17.62 , \text{g}}{159.7 , \text{g/mole}} \approx 0.110 , \text{moles of A} ). If the reaction between compound A and compound B produces compound C in a 1:1 molar ratio, then 0.110 moles of A would yield 0.110 moles of C. Finally, converting moles of C to grams gives ( \text{grams of C} = 0.110 , \text{moles} \times 57.6 , \text{g/mole} \approx 6.35 , \text{g} ).
How many moles of Na SO4 are in 25.0 of this compound?
To find the number of moles of Na2SO4 in 25.0 g of the compound, you need to convert the mass to moles. First, determine the molar mass of Na2SO4, then divide the given mass by the molar mass to obtain the number of moles.
How many grams are there in 3.3 x 1023 moles?
This depends on the molar mass of the compound involved.
How many moles of MgS2O3 are in 215 g of the compound?
To find the number of moles in 215 g of MgS2O3, you first need to calculate the molar mass of the compound. The molar mass of MgS2O3 is 120.3 g/mol. Next, divide the given mass (215 g) by the molar mass to find the number of moles. Therefore, 215 g of MgS2O3 is equal to 1.79 moles.
How many moles of MgS203 are in 211 g of the compound?
To find the number of moles of MgS2O3 in 211 g of the compound, you need to first calculate the molar mass of MgS2O3. This is 120.37 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 211 g / 120.37 g/mol = 1.75 moles of MgS2O3.
How many moles of lithium phosphate are in 51 grams of this substance?
To find the number of moles in 51 grams of lithium phosphate, you first need to determine its molar mass. The molar mass of lithium phosphate (Li3PO4) is 115.79 g/mol. To find the number of moles, divide the given mass by the molar mass: 51 g / 115.79 g/mol ≈ 0.44 moles of lithium phosphate.
How many grams are needed to have 5.00 moles?
This depends on the compound.
How many MOLES of sodium nitrate are present in 2.85 grams of this compound?
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
0.871 moles is how many grams?
Multiply the number of moles by the molecular weight of the compound (or atomic weight for an element) to find the mass in grams.
How many grams of phosphorus trichloride are present in 3.42 moles of this compound?
3,42 moles of phosphorus trichloride have 469,6686 g.
If compound A has a molar mass of 159.7 gmole and compound C has a molar mass of 57.6 gmole how many grams of compound C will be produced from 17.62 grams of compound A and excess compound B?
To determine the grams of compound C produced from 17.62 grams of compound A, we first need to calculate the number of moles of compound A. This is done by dividing the mass of compound A by its molar mass: ( \text{moles of A} = \frac{17.62 , \text{g}}{159.7 , \text{g/mole}} \approx 0.110 , \text{moles of A} ). If the reaction between compound A and compound B produces compound C in a 1:1 molar ratio, then 0.110 moles of A would yield 0.110 moles of C. Finally, converting moles of C to grams gives ( \text{grams of C} = 0.110 , \text{moles} \times 57.6 , \text{g/mole} \approx 6.35 , \text{g} ).
How many moles of Na SO4 are in 25.0 of this compound?
To find the number of moles of Na2SO4 in 25.0 g of the compound, you need to convert the mass to moles. First, determine the molar mass of Na2SO4, then divide the given mass by the molar mass to obtain the number of moles.
How many grams are there in 3.3 x 1023 moles?
This depends on the molar mass of the compound involved.
How many MOLES of dinitrogen tetraoxide are present in 4.00 grams of this compound?
Dinitrogen tetraoxide, or N2O4 has a molar mass of 92.011 grams per mole. This means there are 0.0435 moles present.
How many grams of carbon monoxide (CO) are there in 2.55 moles of the ompound?
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
