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In the reaction 2 RbNO3-- 2 RbN plus 3O2 how many moles of O2 are produced when 5 mol of RbNO3 decompose?

5 moles RbNO3 (3 moles O2/2 moles RbNO3) = 7.5 moles oxygen gas produced


How many moles of CO2 are produced when 2.1 mol of C2H2 react?

How many moles of CO2 are produced when 2.1 mol of C2H2 react?


How many moles of NH3 are produced when 1.2 moles H2 reacts?

How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?


How many moles of NH3 are produced when 1.2 mol of H2 reacts?

The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.


How many moles of NH3 are produced when 1.2 moles of H2 reacts?

How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?


How many moles of KBr will be produced from 14.17 moles of BaBr2?

14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)


How many moles of ions are produced when 2 mol of Na2CO3 dissociate?

Na2CO32 * 2 = 4 moles sodium.===========================


How many moles of N2 reacted if 0.60 mol of NH3 is produced?

0,3 moles of nitrogen reacted.


How many moles of KBr will be produced from 4.79 moles of BaBr2?

14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)


How many moles of CO2 will be produced from 0.33 mol C3H8O in the reaction 2C3H8O plus 9O2 producing 6CO2 and 8H2O?

Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O


How many moles of CO2 are produced when 5.60 mol of ethane are burned in an excess of oxygen?

The balanced equation for the combustion of ethane (C2H6) is: 2C2H6 + 7O2 -> 4CO2 + 6H2O From the equation, for every 2 moles of ethane burned, 4 moles of CO2 are produced. Therefore, if 5.60 mol of ethane are burned, then (5.60 mol / 2 mol ethane) * 4 mol CO2 = 11.2 mol of CO2 are produced.


How many moles of NH3 can be produced from 12.0mol of H2 and excess N2?

8 mol